有没有办法计算 tikz 图片中节点的高度,并将一个长度除以另一个长度以获得计数器并将其四舍五入?如果有,在阅读完使用不同类型的变量进行计算的主题后,我可以在哪里阅读?
以下是一个例子:
\documentclass [a4paper] {article}
\usepackage{calc}
\usepackage{tikz,pgf}
\usetikzlibary{arrows}
%in this case i want to do a framebox with the parameter of 1 line's length in a tikz pictures
%because i dont know how could i get the heigth of the node i try to calculate it by divide the full length of the text (what i got with the command \settototalheight from the calc package) by the length of 1 line (this is a parameter) so i got the number of lines(this is a value not a length so i cannot use the \divide command because the type of the variable)
\newlength \widthofone \fullwidth \heightoneline \fullheight
\nemcounters \numberoflines
\newcommand {\altframe}[2] { %#1 the text #2 the width of the lines
\widthofone=#2pt %im not sure how to convert a length from a value but i try to input the 2nd parameter into a length variable
\settototalheight{\heightoneline}{qwe} %i get the height of one line by the calc package
\setwidth{\totalwidth}{#1} %i calculate the width of the text
%And now i would divide \fullwidth by \widthofone ,if i would know how to do it, to get \numberoflines
%I would multiply it by \height to get \fullheight
\begin{tikzpictures}
\node[text width=#2pt] at (0,0) {#1};%i write out the text
\draw[->,color=black] (\fullwidth/2,\fullheight/2) -- (0-\fullwidth/2,\fullheight/2); %i draw out the lines (i use height/2 becouse of the fact that the (0,0) coordinate is the middle of the picture)
\draw[->,color=black] (\fullwidth/2,0-\fullheight/2) -- (0-\fullwidth/2,0-\fullheight/2);
\draw[->,color=black] (\fullwidth/2,\fullheight/2) -- (\fullwidth/2,0-\fullheight/2);
\draw[->,color=black] (0-\fullwidth/2,\fullheight/2) -- (0-\fullwidth/2,0-\fullheight/2);
\end{tikzpictures}
}
\begin{document}
\altframe{i love this sample text}{100}
\end{document}
答案1
我不知道你要做什么。但对于你的子问题:
计算 tikz 图片中节点的高度
\makeatletter
\newcommand\getheightofnode[2]{%
\pgfextracty{#1}{\pgfpointanchor{#2}{north}}%
\pgfextracty{\pgf@ya}{\pgfpointanchor{#2}{south}}%
\addtolength{#1}{-\pgf@ya}}
\makeatother
用一个长度除以另一个长度
你可以\usetikzlibrary{math}
,只需写
\tikzmath{
\numberoflines=\fullwidth/\widthofone;}
并将其四舍五入
\tikzmath{
\numberoflines=ceil(\fullwidth/\widthofone);}
然而,请注意
- 行数不能这样计算。因为 TeX 倾向于在适当的职位,行数通常较大。
- “一行的(总)高度”不是常数。例如
{x xx}
,{M MM}
和{j jj}
的高度不同。 - 更糟糕的是,“一行的(总)高度在一个段落中' 与给出的 不同
\settototalheight
。通常前者是\baselineskip
,但它可以更大。
所以我猜下面的代码更接近你的方法
\documentclass{article}
\usepackage{calc,tikz}\usetikzlibrary{math}
\newlength\widthofone \newlength\fullwidth \newlength\heightoneline \newlength\fullheight
\makeatletter
\newcommand\getheightofnode[2]{%
\pgfextracty{#1}{\pgfpointanchor{#2}{north}}%
\pgfextracty{\pgf@ya}{\pgfpointanchor{#2}{south}}%
\addtolength{#1}{-\pgf@ya}}
\makeatother
\newcommand {\altframe}[2]{
\widthofone=#2
\heightoneline\baselineskip
\settowidth{\fullwidth}{#1}
\begin{tikzpicture}[->,color=black]
\node[text width=#2](baby)at(0,0){#1};
\getheightofnode\fullheight{baby}
\tikzmath{
\numberoflines=round(\fullheight/\heightoneline);}
\draw(\fullwidth/2,\fullheight/2)--(-\fullwidth/2,\fullheight/2);
\draw(\fullwidth/2,-\fullheight/2)--(-\fullwidth/2,-\fullheight/2);
\draw(\fullwidth/2,\fullheight/2)--(\fullwidth/2,-\fullheight/2);
\draw(-\fullwidth/2,\fullheight/2)--(-\fullwidth/2,-\fullheight/2);
\node[text width=5cm]at(0,-3){
widthofone =\the\widthofone \\
fullwidth =\the\fullwidth \\
heightoneline =\the\heightoneline \\
fullheight =\the\fullheight \\
numberoflines = \numberoflines};
\end{tikzpicture}}
\begin{document}
\altframe{i love this sample text}{50pt}
\end{document}