我怎样才能以更适合导出的方式编写它?

我怎样才能以更适合导出的方式编写它?

这个我用 Circuitikz 绘制的图形是自第一块石头以来我处理的第一个“复杂”图形,但我想知道在未来的项目中是否有可能使它更“可导出”,也就是说,如果改变 FlipFlops 之间的分离,那么不会像现在这样改变很多东西的位置。

以下是我所写的:

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[siunitx, RPvoltages]{circuitikzgit}

\tikzset{flipflop JK/.style={flipflop,
flipflop def={t1=Q, t3={\ctikztextnot{Q}}, t6=J, t4=K,c5=1, td=PRST, 
tu=CLR},
}}

\begin{document}
    \begin{center}
      \begin{circuitikz}[scale=0.8, transform shape]
        \node[vsourcesquareshape, rotate=90](clk){};
         \draw (-3,0) node[flipflop JK,external pins width=0](FF0){};
         \draw (-6,0) node[flipflop JK,external pins width=0](FF1){};
         \draw (-9,0) node[flipflop JK,external pins width=0](FF2){};
         \draw (-12,0) node[flipflop JK,external pins width=0](FF3){};
         \draw (-15,0) node[flipflop JK,external pins width=0](FF4){};

         \draw (clk.north) -- (FF0.east)node[inputarrow,rotate=180]{};
         \draw (FF0.pin 1) -| (-4.5,0);
         \draw (-4.5,0) -- (FF1.pin 5)node[inputarrow,rotate=180]{};

         \draw (FF1.pin 1) -| (-7.5,0);
         \draw (-7.5,0) -- (FF2.pin 5)node[inputarrow,rotate=180]{};

         \draw (FF2.pin 1) -| (-10.5,0);
         \draw (-10.5,0) -- (FF3.pin 5)node[inputarrow,rotate=180]{};

         \draw (FF3.pin 1) -| (-13.5,0);
         \draw (-13.5,0) -- (FF4.pin 5)node[inputarrow,rotate=180]{};

         \draw (FF0.pin 1) -| (-4.5,2)node[inputarrow,rotate=90] 
          {\rotatebox{-90}{$Q_0$}};
         \draw (FF1.pin 1) -| (-7.5,2)node[inputarrow,rotate=90] 
          {\rotatebox{-90}{$Q_1$}};
         \draw (FF2.pin 1) -| (-10.5,2)node[inputarrow,rotate=90] 
          {\rotatebox{-90}{$Q_2$}};
           \draw (FF3.pin 1) -| (-13.5,2)node[inputarrow,rotate=90] 
           {\rotatebox{-90}{$Q_3$}};
           \draw (FF4.pin 1) -| (-16.5,2)node[inputarrow,rotate=90] 
           {\rotatebox{-90}{$Q_4$}};

     \end{circuitikz}
   \end{center}
\end{document}

答案1

我将这个问题解释为希望更容易地全局更改电路的某些功能。这可以通过使用来实现chains\foreach并且正如 Rmano 指出的那样,计算。可以将触发器放在链上,然后在循环中完成其余操作。然后这些参数只出现一次并且可以全局更改。例如,触发器之间的距离由给出node distance

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[siunitx, RPvoltages]{circuitikz}
\usetikzlibrary{calc,chains}
\tikzset{flipflop JK/.style={flipflop,
flipflop def={t1=Q, t3={\ctikztextnot{Q}}, t6=J, t4=K,c5=1, td=PRST, 
tu=CLR},
}}

\begin{document}
    \begin{center}
      \begin{circuitikz}[scale=0.8, transform shape]
         \node[vsourcesquareshape, rotate=90](clk){};
         % do the flip flops     
         \begin{scope}[start chain=going left,node distance=1.5cm,
            nodes={on chain,flipflop JK,external pins width=0}]
            \path foreach \X in {0,...,4}
            {node(FF\X){}};
         \end{scope}
         % determine the midpoints between the flip flops and name them
         \path foreach \X in {1,...,4}
          {(FF\the\numexpr\X-1|-0,0) -- coordinate (c\X) (FF\X|-0,0)};
         % add one more of the points to the left
         \path let \p1=($(FF0.center)-(c1)$) in (FF4.center|-0,0)
          ++ (-\x1,0) coordinate (c5);
         % from original code
         \draw (clk.north) -- (FF0.east)node[inputarrow,rotate=180]{};
         % draw the stuff between those nodes
         \foreach \X in {1,...,4}
         {\draw (FF\the\numexpr\X-1\relax.pin 1) -| (c\X);
          \draw (c\X) -- (FF\X.pin 5)node[inputarrow,rotate=180]{};
          \draw (FF\the\numexpr\X-1\relax.pin 1) -| (c\X|-0,2)node[inputarrow,rotate=90] 
          {\rotatebox{-90}{$Q_{\the\numexpr\X-1\relax}$}};}
         % use c5 
         \draw (FF4.pin 1) -| (c5|-0,2) node[inputarrow,rotate=90] 
            {\rotatebox{-90}{$Q_4$}};
     \end{circuitikz}
   \end{center}
\end{document}

在此处输入图片描述

非常感谢 Rmano 指导我如何运行您的代码。我正在使用circuitikzCTAN 上的最新版本。抱歉,我无法告诉您如何在 overleaf 上获取它,我也不知道如何修复 overleaf 上的问题。

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