这个我用 Circuitikz 绘制的图形是自第一块石头以来我处理的第一个“复杂”图形,但我想知道在未来的项目中是否有可能使它更“可导出”,也就是说,如果改变 FlipFlops 之间的分离,那么不会像现在这样改变很多东西的位置。
以下是我所写的:
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[siunitx, RPvoltages]{circuitikzgit}
\tikzset{flipflop JK/.style={flipflop,
flipflop def={t1=Q, t3={\ctikztextnot{Q}}, t6=J, t4=K,c5=1, td=PRST,
tu=CLR},
}}
\begin{document}
\begin{center}
\begin{circuitikz}[scale=0.8, transform shape]
\node[vsourcesquareshape, rotate=90](clk){};
\draw (-3,0) node[flipflop JK,external pins width=0](FF0){};
\draw (-6,0) node[flipflop JK,external pins width=0](FF1){};
\draw (-9,0) node[flipflop JK,external pins width=0](FF2){};
\draw (-12,0) node[flipflop JK,external pins width=0](FF3){};
\draw (-15,0) node[flipflop JK,external pins width=0](FF4){};
\draw (clk.north) -- (FF0.east)node[inputarrow,rotate=180]{};
\draw (FF0.pin 1) -| (-4.5,0);
\draw (-4.5,0) -- (FF1.pin 5)node[inputarrow,rotate=180]{};
\draw (FF1.pin 1) -| (-7.5,0);
\draw (-7.5,0) -- (FF2.pin 5)node[inputarrow,rotate=180]{};
\draw (FF2.pin 1) -| (-10.5,0);
\draw (-10.5,0) -- (FF3.pin 5)node[inputarrow,rotate=180]{};
\draw (FF3.pin 1) -| (-13.5,0);
\draw (-13.5,0) -- (FF4.pin 5)node[inputarrow,rotate=180]{};
\draw (FF0.pin 1) -| (-4.5,2)node[inputarrow,rotate=90]
{\rotatebox{-90}{$Q_0$}};
\draw (FF1.pin 1) -| (-7.5,2)node[inputarrow,rotate=90]
{\rotatebox{-90}{$Q_1$}};
\draw (FF2.pin 1) -| (-10.5,2)node[inputarrow,rotate=90]
{\rotatebox{-90}{$Q_2$}};
\draw (FF3.pin 1) -| (-13.5,2)node[inputarrow,rotate=90]
{\rotatebox{-90}{$Q_3$}};
\draw (FF4.pin 1) -| (-16.5,2)node[inputarrow,rotate=90]
{\rotatebox{-90}{$Q_4$}};
\end{circuitikz}
\end{center}
\end{document}
答案1
我将这个问题解释为希望更容易地全局更改电路的某些功能。这可以通过使用来实现chains
,\foreach
并且正如 Rmano 指出的那样,计算。可以将触发器放在链上,然后在循环中完成其余操作。然后这些参数只出现一次并且可以全局更改。例如,触发器之间的距离由给出node distance
。
\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage[siunitx, RPvoltages]{circuitikz}
\usetikzlibrary{calc,chains}
\tikzset{flipflop JK/.style={flipflop,
flipflop def={t1=Q, t3={\ctikztextnot{Q}}, t6=J, t4=K,c5=1, td=PRST,
tu=CLR},
}}
\begin{document}
\begin{center}
\begin{circuitikz}[scale=0.8, transform shape]
\node[vsourcesquareshape, rotate=90](clk){};
% do the flip flops
\begin{scope}[start chain=going left,node distance=1.5cm,
nodes={on chain,flipflop JK,external pins width=0}]
\path foreach \X in {0,...,4}
{node(FF\X){}};
\end{scope}
% determine the midpoints between the flip flops and name them
\path foreach \X in {1,...,4}
{(FF\the\numexpr\X-1|-0,0) -- coordinate (c\X) (FF\X|-0,0)};
% add one more of the points to the left
\path let \p1=($(FF0.center)-(c1)$) in (FF4.center|-0,0)
++ (-\x1,0) coordinate (c5);
% from original code
\draw (clk.north) -- (FF0.east)node[inputarrow,rotate=180]{};
% draw the stuff between those nodes
\foreach \X in {1,...,4}
{\draw (FF\the\numexpr\X-1\relax.pin 1) -| (c\X);
\draw (c\X) -- (FF\X.pin 5)node[inputarrow,rotate=180]{};
\draw (FF\the\numexpr\X-1\relax.pin 1) -| (c\X|-0,2)node[inputarrow,rotate=90]
{\rotatebox{-90}{$Q_{\the\numexpr\X-1\relax}$}};}
% use c5
\draw (FF4.pin 1) -| (c5|-0,2) node[inputarrow,rotate=90]
{\rotatebox{-90}{$Q_4$}};
\end{circuitikz}
\end{center}
\end{document}
非常感谢 Rmano 指导我如何运行您的代码。我正在使用circuitikz
CTAN 上的最新版本。抱歉,我无法告诉您如何在 overleaf 上获取它,我也不知道如何修复 overleaf 上的问题。