使用 hexdump -C 时“*”是什么意思?

使用 hexdump -C 时“*”是什么意思?

我一直在做一项练习,试图了解程序背后发生的一些事情。我编写了一个小型 C 程序,并在 i386 Linux (Ubuntu 12.04) 上使用gcc.然后我hexdump -C对输出到文本文件进行了操作。我注意到偏移量上有一些间隙*

00000670  00 3f 1a 3b 2a 32 24 22  1c 00 00 00 40 00 00 00  |.?.;*2$"....@...|
00000680  94 fd ff ff 05 01 00 00  00 41 0e 08 85 02 42 0d  |.........A....B.|
00000690  05 03 01 01 c5 0c 04 04  38 00 00 00 60 00 00 00  |........8...`...|
000006a0  80 fe ff ff 61 00 00 00  00 41 0e 08 85 02 41 0e  |....a....A....A.|
000006b0  0c 87 03 41 0e 10 86 04  41 0e 14 83 05 4e 0e 30  |...A....A....N.0|
000006c0  02 4a 0e 14 41 0e 10 c3  41 0e 0c c6 41 0e 08 c7  |.J..A...A...A...|
000006d0  41 0e 04 c5 10 00 00 00  9c 00 00 00 b4 fe ff ff  |A...............|
000006e0  02 00 00 00 00 00 00 00  10 00 00 00 b0 00 00 00  |................|
000006f0  a2 fe ff ff 04 00 00 00  00 00 00 00 00 00 00 00  |................|
00000700  00 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |................|
*
00000f10  00 00 00 00 ff ff ff ff  00 00 00 00 ff ff ff ff  |................|
00000f20  00 00 00 00 00 00 00 00  01 00 00 00 10 00 00 00  |................|
00000f30  0c 00 00 00 d4 82 04 08  0d 00 00 00 cc 85 04 08  |................|
00000f40  f5 fe ff 6f ac 81 04 08  05 00 00 00 2c 82 04 08  |...o........,...|
00000f50  06 00 00 00 cc 81 04 08  0a 00 00 00 54 00 00 00  |............T...|
00000f60  0b 00 00 00 10 00 00 00  15 00 00 00 00 00 00 00  |................|
00000f70  03 00 00 00 f4 9f 04 08  02 00 00 00 20 00 00 00  |............ ...|
00000f80  14 00 00 00 11 00 00 00  17 00 00 00 b4 82 04 08  |................|
00000f90  11 00 00 00 ac 82 04 08  12 00 00 00 08 00 00 00  |................|
00000fa0  13 00 00 00 08 00 00 00  fe ff ff 6f 8c 82 04 08  |...........o....|
00000fb0  ff ff ff 6f 01 00 00 00  f0 ff ff 6f 80 82 04 08  |...o.......o....|
00000fc0  00 00 00 00 00 00 00 00  00 00 00 00 00 00 00 00  |................|
*
00000ff0  00 00 00 00 28 9f 04 08  00 00 00 00 00 00 00 00  |....(...........|
00001000  26 83 04 08 36 83 04 08  46 83 04 08 56 83 04 08  |&...6...F...V...|
00001010  00 00 00 00 00 00 00 00  47 43 43 3a 20 28 55 62  |........GCC: (Ub|
00001020  75 6e 74 75 2f 4c 69 6e  61 72 6f 20 34 2e 36 2e  |untu/Linaro 4.6.|
00001030  33 2d 31 75 62 75 6e 74  75 35 29 20 34 2e 36 2e  |3-1ubuntu5) 4.6.|
00001040  33 00 00 2e 73 79 6d 74  61 62 00 2e 73 74 72 74  |3...symtab..strt|
00001050  61 62 00 2e 73 68 73 74  72 74 61 62 00 2e 69 6e  |ab..shstrtab..in|
00001060  74 65 72 70 00 2e 6e 6f  74 65 2e 41 42 49 2d 74  |terp..note.ABI-t|
00001070  61 67 00 2e 6e 6f 74 65  2e 67 6e 75 2e 62 75 69  |ag..note.gnu.bui|
00001080  6c 64 2d 69 64 00 2e 67  6e 75 2e 68 61 73 68 00  |ld-id..gnu.hash.|
00001090  2e 64 79 6e 73 79 6d 00  2e 64 79 6e 73 74 72 00  |.dynsym..dynstr.|

我的问题是,我应该如何解释*?我认为这意味着文件中存在间隙,但问题就变成了为什么会存在间隙?这是 ELF 文件标准格式的一部分吗?

答案1

与标准od命令 或一样hd,这意味着所有省略的行与前一行相同。无论如何,您可以通过-v让它显示这些行。从hexdump(1)

-v 选项使 hexdump 显示所有输入数据。如果没有 -v 选项,任意数量的输出行组(与紧邻的前一组输出行相同(输入偏移量除外))将被替换为由单个星号组成的行。

相关内容