我试图查找带有回车符的行,但我没有得到我期望的结果。我将其简化为这个概念验证:
$ uname -a
CYGWIN_NT-6.1 Aodh 2.0.4(0.287/5/3) 2015-06-09 12:22 x86_64 Cygwin
$ grep --version
grep (GNU grep) 2.21
Copyright (C) 2014 Free Software Foundation, Inc.
License GPLv3+: GNU GPL version 3 or later <http://gnu.org/licenses/gpl.html>.
This is free software: you are free to change and redistribute it.
There is NO WARRANTY, to the extent permitted by law.
Written by Mike Haertel and others, see <http://git.sv.gnu.org/cgit/grep.git/tree/AUTHORS>.
$ od -c cr_poc.txt
0000000 h e l l o w o r l d ; \r \n \r \n
0000020
$ od -x cr_poc.txt
0000000 6568 6c6c 206f 6f77 6c72 3b64 0a0d 0a0d
0000020
$ grep $'\r' cr_poc.txt; echo $?
1
我尝试过各种其他方式来查找\r
角色,但没有一个有效。
请注意,这是在 Cygwin 上,这当然可能是问题的一部分。
答案1
通过研究各种输入,我觉得grep
它对行结束有自己的魔力:
$ printf "foo\rbar\n" | grep -oz $'\r' | od -c
0000000 \r \n
0000002
$ printf "foo\rbar\r\n" | grep -oz $'\r' | od -c
0000000
$ printf "foo\rbar\r" | grep -oz $'\r' | od -c
0000000 \r \n \r \n
0000004
(这-z
是我试图匹配所有内容的蹩脚尝试grep
。)因此我在联机帮助页中搜索了LF
,导致我:
-U, --binary
Treat the file(s) as binary. By default, under MS-DOS and MS-
Windows, grep guesses the file type by looking at the contents
of the first 32KB read from the file. If grep decides the file
is a text file, it strips the CR characters from the original
file contents (to make regular expressions with ^ and $ work
correctly). Specifying -U overrules this guesswork, causing all
files to be read and passed to the matching mechanism verbatim;
if the file is a text file with CR/LF pairs at the end of each
line, this will cause some regular expressions to fail. This
option has no effect on platforms other than MS-DOS and MS-
Windows.