使应用程序静音的脚本

Question 1

以下是我对您这个有趣挑战的看法：

#!/bin/bash

main() {
    local action=mute
    while getopts :hu option; do 
        case "$option" in 
            h) usage 0 ;;
            u) action=unmute ;;
            ?) usage 1 "invalid option: -$OPTARG" ;;
        esac
    done
    shift $((OPTIND - 1))

    if [[ "$1" ]]; then
        $action "$1"
    else
        usage 1 "specify an application name" 
    fi
}

usage() {
    [[ "$2" ]] && echo "error: $2"
    echo "usage: $0 [-h] [-u] appname"
    echo "where: -u = ummute application (default action is to mute)"
    exit $1
}

mute()   { adjust_muteness "$1" 1; }
unmute() { adjust_muteness "$1" 0; }

adjust_muteness() { 
    local index=$(get_index "$1")
    [[ "$index" ]] && pacmd set-sink-input-mute "$index" $2 >/dev/null 
}

get_index() {
    local pid=$(pidof "$1")
    if [[ -z "$pid" ]]; then
        echo "error: no running processes for: $1" >&2
    else
        pacmd list-sink-inputs | 
        awk -v pid=$pid '
            $1 == "index:" {idx = $2} 
            $1 == "application.process.id" && $3 == "\"" pid "\"" {print idx; exit}
        '
    fi
}

main "$@"

Answer

以下是我对您这个有趣挑战的看法：

#!/bin/bash

main() {
    local action=mute
    while getopts :hu option; do 
        case "$option" in 
            h) usage 0 ;;
            u) action=unmute ;;
            ?) usage 1 "invalid option: -$OPTARG" ;;
        esac
    done
    shift $((OPTIND - 1))

    if [[ "$1" ]]; then
        $action "$1"
    else
        usage 1 "specify an application name" 
    fi
}

usage() {
    [[ "$2" ]] && echo "error: $2"
    echo "usage: $0 [-h] [-u] appname"
    echo "where: -u = ummute application (default action is to mute)"
    exit $1
}

mute()   { adjust_muteness "$1" 1; }
unmute() { adjust_muteness "$1" 0; }

adjust_muteness() { 
    local index=$(get_index "$1")
    [[ "$index" ]] && pacmd set-sink-input-mute "$index" $2 >/dev/null 
}

get_index() {
    local pid=$(pidof "$1")
    if [[ -z "$pid" ]]; then
        echo "error: no running processes for: $1" >&2
    else
        pacmd list-sink-inputs | 
        awk -v pid=$pid '
            $1 == "index:" {idx = $2} 
            $1 == "application.process.id" && $3 == "\"" pid "\"" {print idx; exit}
        '
    fi
}

main "$@"

Question 2

谢谢你的解决方案！我设法使用这里提供的脚本来解决我的问题。由于我不得不对它们进行一些修改，所以我在这里加入了改进的版本。

原始脚本对我不起作用的原因是，某些应用程序可以有多个实例，即多个 PID，但可能只有其中一个产生声音，因此实际上连接到 Pulseaudio。由于脚本仅使用找到的第一个 PID，因此它通常不会使所需应用程序静音。

因此，这里有一个版本，其中参数是 PulseAudio 中注册的应用程序名称。您可以通过运行命令pacmd list-sink-inputs并查找application.name字段来找到此名称。

另一种解决方案是将所有具有相同应用程序名称的 PID 静音/取消静音。

#!/bin/bash

# Adapter from glenn jackman on http://askubuntu.com/questions/180612/script-to-mute-an-application
# to depend directly on the name of the PulseAudio client
# rather than the application name (several instances of one application could
# run while only one is connected to PulseAudio)

# Possible further improvement: it could be useful to also mute all clients having
# the specified name. Here, only the first one is muted.

#!/bin/bash

main() {
    local action=mute
    while getopts :hu option; do
        case "$option" in
            h) usage 0 ;;
            u) action=unmute ;;
            ?) usage 1 "invalid option: -$OPTARG" ;;
        esac
    done
    shift $((OPTIND - 1))

    if [[ "$1" ]]; then
        $action "$1"
    else
        usage 1 "specify the name of a PulseAudio client"
    fi
}

usage() {
    [[ "$2" ]] && echo "error: $2"
    echo "usage: $0 [-h] [-u] appname"
    echo "where: -u = ummute application (default action is to mute)"
    exit $1
}

mute()   { adjust_muteness "$1" 1; }
unmute() { adjust_muteness "$1" 0; }

adjust_muteness() {
    local index=$(get_index "$1")
    if [[ -z "$index" ]]; then
        echo "error: no PulseAudio sink named $1 was found" >&2
    else
        [[ "$index" ]] && pacmd set-sink-input-mute "$index" $2 >/dev/null
    fi
}

get_index() {
#    local pid=$(pidof "$1")
#    if [[ -z "$pid" ]]; then
#        echo "error: no running processes for: $1" >&2
#    else
        pacmd list-sink-inputs |
        awk -v name=$1 '
            $1 == "index:" {idx = $2}
            $1 == "application.name" && $3 == "\"" name "\"" {print idx; exit}
        '
#    fi
}

main "$@"

Answer

谢谢你的解决方案！我设法使用这里提供的脚本来解决我的问题。由于我不得不对它们进行一些修改，所以我在这里加入了改进的版本。

原始脚本对我不起作用的原因是，某些应用程序可以有多个实例，即多个 PID，但可能只有其中一个产生声音，因此实际上连接到 Pulseaudio。由于脚本仅使用找到的第一个 PID，因此它通常不会使所需应用程序静音。

因此，这里有一个版本，其中参数是 PulseAudio 中注册的应用程序名称。您可以通过运行命令pacmd list-sink-inputs并查找application.name字段来找到此名称。

另一种解决方案是将所有具有相同应用程序名称的 PID 静音/取消静音。

#!/bin/bash

# Adapter from glenn jackman on http://askubuntu.com/questions/180612/script-to-mute-an-application
# to depend directly on the name of the PulseAudio client
# rather than the application name (several instances of one application could
# run while only one is connected to PulseAudio)

# Possible further improvement: it could be useful to also mute all clients having
# the specified name. Here, only the first one is muted.

#!/bin/bash

main() {
    local action=mute
    while getopts :hu option; do
        case "$option" in
            h) usage 0 ;;
            u) action=unmute ;;
            ?) usage 1 "invalid option: -$OPTARG" ;;
        esac
    done
    shift $((OPTIND - 1))

    if [[ "$1" ]]; then
        $action "$1"
    else
        usage 1 "specify the name of a PulseAudio client"
    fi
}

usage() {
    [[ "$2" ]] && echo "error: $2"
    echo "usage: $0 [-h] [-u] appname"
    echo "where: -u = ummute application (default action is to mute)"
    exit $1
}

mute()   { adjust_muteness "$1" 1; }
unmute() { adjust_muteness "$1" 0; }

adjust_muteness() {
    local index=$(get_index "$1")
    if [[ -z "$index" ]]; then
        echo "error: no PulseAudio sink named $1 was found" >&2
    else
        [[ "$index" ]] && pacmd set-sink-input-mute "$index" $2 >/dev/null
    fi
}

get_index() {
#    local pid=$(pidof "$1")
#    if [[ -z "$pid" ]]; then
#        echo "error: no running processes for: $1" >&2
#    else
        pacmd list-sink-inputs |
        awk -v name=$1 '
            $1 == "index:" {idx = $2}
            $1 == "application.name" && $3 == "\"" name "\"" {print idx; exit}
        '
#    fi
}

main "$@"

Question 3

尽管问题要求提供脚本，但我还是想将其留在这里。

我在 Ubuntu 上编写了一个 C 应用程序来实现这一点。更棒的是，它位于指示器托盘上（使用libappindicator），并在短时间内检查 Spotify 正在播放的内容。如果它正在播放广告（对照黑名单检查），它会将 Spotify 静音。如果正在播放新广告，您只需单击指示器菜单上的静音，它就会将其添加到黑名单中。

它的作用是查找 X 窗口，并XFetchName返回Spotify - Linux Preview。然后它调用XGetWindowProperty查询_NET_WM_ICON_NAME该窗口的属性，并返回格式为的字符串"Spotify – <Artist> – <Song>"。播放广告时，它会返回如下内容：

"Spotify – Spotify – Premium Free Trial Cancel Any Time"

它保持着三叉搜索树广告列表，以有效地检查当前标题是否在列表中。

它还使用PulseAudio 异步 API查询sink-inputs和set-mute：

pa_context_get_sink_input_info_list()
pa_context_set_sink_input_mute()

由于它只是简单的 C 代码，因此它很轻量。请查看以下位置的源代码和 Ubuntu.deb软件包：指示剂。它的性能可能比 shell 脚本高出 2-3 个数量级。

Answer