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sort 可以排序 1 2 3 4..9 而不是 1 10 11 12.. 2 20

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sort 可以排序 1 2 3 4..9 而不是 1 10 11 12.. 2 20

我使用这个脚本来在线发现IP

#!/bin/sh
set -e

# no args
if [ $# -lt 1 ]; then
    echo "Too few args"
    echo "Options are:"
    echo "-a: Tell me which host is online"
    echo "-b: show only list of ip found"
    exit 1
fi

# too many args
if [ $# -gt 1 ]; then
    echo "$1 option unknown"
    echo "Options are:"
    echo "-a: Tell me which host is online"
    echo "-b: show only list of ip found"
    exit 1
fi



case $1 in
-a)
array1=(
`nmap -sP 192.168.0.0/24 | awk '/is up/ {print up}; {gsub (/\(|\)/,""); up = $NF}'`
)
for i in ${array1[@]};do echo "Ip $i is online";done
;;
-b)
nmap -sP 192.168.0.0/24 | awk '/is up/ {print up}; {gsub (/\(|\)/,""); up = $NF}'|sort -fn
;;
*)
    echo "$1 option unknown"
    echo "Options are:"
    echo "-a: Tell me which host is online"
    echo "-b: show only list of ip found"
;;
esac

但使用 -b 返回这样的列表

192.168.0.1
192.168.0.11
192.168.0.14
192.168.0.15
192.168.0.17
192.168.0.2
192.168.0.3
192.168.0.44
192.168.0.46
192.168.0.49
192.168.0.50

我想要这样的列表排序

    192.168.0.1
    192.168.0.2
    192.168.0.3
    192.168.0.11
    192.168.0.14
    192.168.0.15
    192.168.0.22
    192.168.0.44
    192.168.0.46
    192.168.0.49
    192.168.0.50

有什么排序建议吗？

答案1

sort.仅根据分隔的第四个字段：

... | sort -t. -k4,4n

  • -t.将输入字段分隔符设置为.

  • --k4,4n仅根据第4个字段对文件进行排序，并n实现数字排序

例子：

$ cat file.txt
192.168.0.1
192.168.0.11
192.168.0.14
192.168.0.15
192.168.0.17
192.168.0.2
192.168.0.3
192.168.0.44
192.168.0.46
192.168.0.49
192.168.0.50

$ sort -t. -k4,4n file.txt
192.168.0.1
192.168.0.2
192.168.0.3
192.168.0.11
192.168.0.14
192.168.0.15
192.168.0.17
192.168.0.44
192.168.0.46
192.168.0.49
192.168.0.50

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