使用 shell 命令将文本中存在的字节分成 3 列

使用 shell 命令将文本中存在的字节分成 3 列

我有一个文件input.txt,其中包含以下几个段落:

[730480.910190] [MACSTATUSIND] ACTIND_ParseMACSTATUS:
[730480.910205] fe 0a 39 01 0a 00 51 e7 ba 9d c7 0d 00 00 00 00  ..9...Q....
[730480.910220] 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ...........
[730480.910233] 00 00 00 00 00 00 00 00 00 00 xx xx xx xx xx xx  .....:bC.B.
[730480.910247] xx xx yy yy yy yy yy yy zz zz 64 34 e8 ff 00 00  ......d4...

[730480.910190] [MACSTATUSIND] ACTIND_ParseMACSTATUS:
[730480.910205] fe 0a 39 01 0a 00 51 e7 ba 9d c7 0d 00 00 00 00  ..9...Q....
[730480.910220] 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00 00  ...........
[730480.910233] 00 00 00 00 00 00 00 00 00 00 aa bb cc dd ee ff .....:bC.B.
[730480.910247] gg hh ii jj kk ll mm nn oo pp 64 34 e8 ff 00 00  ......d4...

根据上面的数据,对于每个段落,我想制作三列,然后将这些行存储在不同的/新文件中new.txt

输出:new.txt

   col1    col2     col3
  -------  ----    ------
xxxxxxxx   | yyyyyy |  zzzz
aabb..gghh | ii..nn |  oopp       

笔记:上述段落日志在文件中重复多次。所有段落都应具有以[MACSTATUSIND] ACTIND_ParseMACSTATUS:

答案1

awk 'BEGIN { print "     col1        |     col2     | col3" }
    /^\[730480.910233\] / {SA = $12 $13 $14 $15 $16 $17}
    /^\[730480.910247\] / { print SA $2 $3 " | " $4 $5 $6 $7 $8 $9 " | " $10 $11}
'  input.txt > new.txt

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