我有一个目录/home/ubuntu/上传。我需要检查它是否包含任何 zip 文件。如果它包含,那么我需要根据日期将最旧的修改文件移动到另一个名为/home/ubuntu/temp。然后我需要解压我们得到的zip文件 /home/ubuntu/temp 到一个名为/home/ubuntu/s3。最后我需要将文件标记为已成功移动。
这是我在 bash 脚本中所做的 ->
#!/bin/bash
if [[ -z `ls -t /home/ubuntu/uploads/*.zip | tail -1` ]] ; then
echo 'No new zip file to move !'
exit
fi
TIME=`date +%Y-%m-%d_%H-%M-%S`
UPLOADS='/home/ubuntu/uploads'
TEMP='/home/ubuntu/temp'
BUCKET='/home/ubuntu/s3'
FILENAME=`ls -t /home/ubuntu/uploads/*.zip | tail -1 | xargs -n 1 basename `
FILEPATH=`ls -t /home/ubuntu/uploads/*.zip | tail -1`
cp $FILEPATH $TEMP
unzip -u $TEMP/"$FILENAME" -d $BUCKET
rm -rf $TEMP/*
mv /home/ubuntu/uploads/"$FILENAME" /home/ubuntu/uploads/"$FILENAME".success.$TIME
它可以工作,但无法处理包含空格的 zip 文件名。
如果有人可以建议一个更好的和改进的版本,请
答案1
这有效..谢谢大家!
#!/bin/bash
# logs last error
#exec 3>&1 4>&2
#trap 'exec 2>&4 1>&3' 0 1 2 3
#exec 1>log.out 2>&1
# check for file names with space and rename
for file in /home/ubuntu/uploads/*' '*
do
if [ -e "${file// /_}" ]
then
printf >&2 '%s\n' "Warning, skipping $file as the renamed version already exists"
continue
fi
mv -- "$file" "${file// /_}"
done
# check for zip files
if [[ -z `ls -t /home/ubuntu/uploads/*.zip | tail -1` ]] ; then
echo 'No new zip file to move !'
exit
fi
# check for bad zip file and remove
shopt -s dotglob nullglob globstar
for file in /home/ubuntu/uploads/*.zip; do
[[ -r $file ]] || continue
unzip -t "$file" >/dev/null 2>&1 || rm -f "$file"
done
TIME=`date +%Y-%m-%d_%H-%M-%S`
UPLOADS='/home/ubuntu/uploads'
TEMP='/home/ubuntu/temp'
BUCKET='/home/ubuntu/s3'
FILENAME=`ls -t /home/ubuntu/uploads/*.zip | tail -1 | xargs -n 1 basename `
FILEPATH=`ls -t /home/ubuntu/uploads/*.zip | tail -1`
cp $FILEPATH $TEMP
unzip -u $TEMP/$FILENAME -d $BUCKET
rm -rf $TEMP/*
mv /home/ubuntu/uploads/"$FILENAME" /home/ubuntu/uploads/"$FILENAME".success.$TIME