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螺旋线的绘制

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螺旋线的绘制

在这个博客我找到了 Thomas Söll 绘制的变压器 3D 图纸。

经过一些更改后，我得到了以下代码：

\documentclass{article}

\usepackage{pst-solides3d}
\usepackage{expl3}

% Parameters.
\def\radius{1.11}
\def\windingsOne{32}
\def\windingsTwo{64}

% Activating floating point calculation.
\ExplSyntaxOn
  \cs_new_eq:NN
    \calc
  \fp_eval:n
\ExplSyntaxOff

% Constants.
\def\factor{\calc{5*\windingsTwo}}
\def\lengthA{\calc{2*pi*\windingsOne/\factor}}
\def\lengthB{\calc{2/5*pi}}
\def\vertDist{\calc{3/4*pi}}
\def\thickness{\calc{16/(25*\windingsTwo)}}
% Global setup.
\psset{%
  viewpoint=20 5 15 rtp2xyz,
  lightsrc=20 60 60 rtp2xyz,
  Decran=30
}
\psset{%
  solidmemory,
  algebraic
}
% Objects with predefined options.
\newpsobject{core}{psSolid}{%
  object=parallelepiped,
  incolor=red,
  fillcolor=cyan!50,
  grid=false
}
\newpsobject{wire}{psSolid}{
  object=courbe,
  r=\thickness,
  linewidth=0.5pt,
  linecolor=red!60,
  incolor=red!60,
  fillcolor=red!60,
  resolution=727,
  ngrid=727 30,
  action=none
}
\newpsobject{connect}{psSolid}{
  object=fusion,
  linecolor=gray,
  grid=false,
  action=draw**
}

\pagestyle{empty}

\begin{document}

\begin{figure}[htbp]
\centering
\begin{pspicture}(-3,-3)(8,8)
% --------------- Core ---------------
\core[a=1,b=5,c=1,action=draw**,name=H1](0,1.5,-0.5)
\core[a=1,b=1,c=3,action=none,name=H2](0,-0.5,1.5)
\core[a=1,b=1,c=3,action=none,name=H3](0,3.5,1.5)
% --------------- Wire ---------------
{\defFunction{helixA}(t){\radius*cos(\factor*t)}{\radius*sin(\factor*t)}{\vertDist*t}
\wire[function=helixA,range=0 \lengthA,name=wire1](0,-0.5,0)}%
{\defFunction{helixB}(t){\radius*cos(\factor*t)}{-\radius*sin(\factor*t)}{\vertDist*t}
\wire[function=helixB,range=0 \lengthB,name=wire2](0,3.5,0)}%
% ------------- Assembly -------------
\connect[base=H2 wire1]
\connect[base=H3 wire2]
\composeSolid
\core[a=1,b=5,c=1,action=draw**,name=H4](0,1.5,3.5)
\end{pspicture}
\end{figure}

\end{document}

\factor我的问题是，常数、\lengthA、\lengthB、\vertDist和的值\thickness是手动找到的。有人能告诉我，如果它们应该取决于变压器铁芯周围的绕组数，那么它们到底应该是多少吗？

PS 代码需要很长时间（在我的计算机上大约 1 分钟）来编译，所以如果有人可以告诉我如何缩短编译时间，请告诉我！

最终版本

\documentclass{article}

\usepackage{pst-solides3d}

%% Parameters
% Windings
\def\lWind{60}
\def\rWind{30}
% Radii
\def\rHelix{1.13}
\def\rWire{0.006}

% Constants
\def\factor{160} % \factor > \lWind,\rWind
\pstVerb{%
  /left 2 \lWind\space mul \factor\space div def
  /right 2 \rWind\space mul \factor\space div def
}

%% Colours
\colorlet{wireColor}{red!60}
\colorlet{coreColor}{cyan!50}
%% Wire
\newpsobject{wire}{psSolid}{%
  object=courbe,
   % Choose max(left,right)
   % The smaller max(left,right), the larger the constant multiplied with it
  ngrid=970 left mul cvi 15,
  r=\rWire,
  fillcolor=wireColor,
  incolor=wireColor
}

\pagestyle{empty}

\begin{document}

\begin{figure}[htbp]
\centering
 \begin{pspicture}(-5,-5)(5,5)
  \psset{%
    algebraic,
    viewpoint=20 5 10 rtp2xyz,
    lightsrc=20 60 60 rtp2xyz,
    Decran=30,
    solidmemory,
    action=none,
    grid=false
  }
  %%--------- Core ----------
  \psSolid[object=anneau,h=1.0,R=4,r=2.5,ngrid=4,RotZ=90,RotY=45,RotX=90,
    fillcolor=coreColor,name=core]
  %%--------- Wire ----------
  % Left
  \defFunction{heliceA}(t){\rHelix*cos(\factor*t)}{\rHelix*sin(\factor*t)}{t/left}
  \wire[function=heliceA,range=0 Pi left mul,name=wireA](0,-2.25,-1.5)
  % Right
  \defFunction{heliceB}(t){\rHelix*cos(\factor*t)}{-\rHelix*sin(\factor*t)}{t/right}
  \wire[function=heliceB,range=0 Pi right mul,name=wireB](0,2.25,-1.5)
  %%------- Assembly --------
  \psSolid[object=fusion,base=core wireA wireB,action=draw**]
 \end{pspicture}
\end{figure}

\end{document}

答案1

首先：创建最小示例！在这里，您是否会说丹麦语并不重要！

\documentclass{minimal}
\pagestyle{empty}
\usepackage{pst-solides3d}
\begin{document}

\def\Ra{1} \def\Rb{0.025}
\def\F{80}
\def\Nleft{0.75 } \def\Nright{0.25 }% Max wire is 1

\begin{pspicture}(-5,-5)(5,5)
\psset{viewpoint=20 5 10 rtp2xyz,lightsrc=20 60 60 rtp2xyz,Decran=30,solidmemory,
  action=none,grid=false,fillcolor=cyan!50}
%--------- iron ---------------------------------------
\psSolid[object=anneau,h=1.,R=4,r=2.5,ngrid=4,RotZ=90,RotY=45,RotX=90,name=iron]
%--------- wire -------------------------------------
\defFunction[algebraic]{heliceA}(t){\Ra*cos(\F*t)}{\Ra*sin(\F*t)}{t/\Nleft}% left  
\psSolid[object=courbe,range=0 3 \Nleft mul,function=heliceA,r=\Rb,
  fillcolor=red!60,incolor=red!60,ngrid=720 \Nleft mul cvi 15,name=wire1](0,-2.25,-1.5)
%  
\defFunction[algebraic]{heliceB}(t){\Ra*cos(\F*t)}{-\Ra*sin(\F*t)}{t/\Nright}% right
\psSolid[object=courbe,range=0 3 \Nright mul,function=heliceB,r=\Rb,
  fillcolor=red!60,incolor=red!60,ngrid=720 \Nleft mul cvi 15,name=wire2](0,2.25,-1.5)
%-------- Compose -------------------------------------
\psSolid[object=fusion,base=iron wire1 wire2,action=draw**]
\end{pspicture}

\end{document}

在此处输入图片描述

与

\def\Nleft{0.2 } \def\Nright{0.1 }% Max wire is 1


在此处输入图片描述

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