我想要一个包围 A、AC 和 C 的矩形，就像包围 B、BC 和 C 的黄色矩形一样（我同样想要一个包围 A、AB 和 B 的矩形），但我找不到任何方法。当我像对 B、BC 和 C 所做的那样尝试时，矩形变得很大
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{shapes,backgrounds,shapes.misc, positioning,shapes.geometric,arrows,matrix,fit,calc}
\tikzset{
buffer/.style={
isosceles triangle,
isosceles triangle apex angle=66,
shape border rotate=90,
fill=blue!20,
node distance=5cm,
rounded corners=60pt,
opacity=0.6,
minimum height=6cm
}
}
\begin{document}
\begin{tikzpicture}
\tikzset{venn circle/.style={draw,circle,minimum width=9mm,fill=#1,opacity=0.6}}
\node at (0,0) {A};
\node (ABC) at (0,-2 ) {ABC};
\node (B) at (-2,-3) {B};
\node (AB) at (-1,-1.5) {AB};
\node (AC) at (1,-1.5) {AC};
\node (BC) at (0,-3) {BC};
\node (C) at (2,-3) {C};
\node[buffer]at (0,-1.9){};
\node[draw, thick, rounded corners = 2.5ex, fit=(B) (C),inner sep=3mm, opacity = 0.6, fill = yellow](FIt1) {};
\node[venn circle = green, thick] at (0,0) {A};
\node (ABC) at (0,-2 ) {ABC};
\node[venn circle = green, thick] (B) at (-2,-3) {B};
\node (AB) at (-1,-1.5) {AB};
\node (AC) at (1,-1.5) {AC};
\node (BC) at (0,-3) {BC};
\node[venn circle = green, thick] (C) at (2,-3) {C};
\end{tikzpicture}
\end{document}
我有一个子问题是，是否可以在这里画一条轮廓线，在黄色、红色和蓝色形状周围画一条黑线
\begin{tikzpicture}[font=\sffamily\sansmath]
\tikzset{venn circle/.style={circle,minimum width=9mm,fill=#1,opacity=0.6}}
\node at (0,0) {A};
\node (ABC) at (0,-2 ) {ABC};
\node (B) at (-2,-3) {B};
\node (AB) at (-1,-1.5) {AB};
\node (AC) at (1,-1.5) {AC};
\node (BC) at (0,-3) {BC};
\node (C) at (2,-3) {C};
\node[buffer]at (0,-1.9){};
\draw [line width=35pt,opacity=0.6,blue,line cap=round,rounded corners] (A.center) -- (AC.center) -- (C.center);
\draw [line width=35pt,opacity=0.6,yellow,line cap=round,rounded corners] (C.center) -- (BC.center) -- (B.center);
\draw [line width=35pt,opacity=0.6,red,line cap=round,rounded corners] (A.center) -- (AB.center) -- (B.center);
\node[venn circle = green, thick] at (0,0) {A};
\node (ABC) at (0,-2 ) {ABC};
\node[venn circle = green, thick] (B) at (-2,-3) {B};
\node (AB) at (-1,-1.5) {AB};
\node (AC) at (1,-1.5) {AC};
\node (BC) at (0,-3) {BC};
\node[venn circle = green, thick] (C) at (2,-3) {C};
\end{tikzpicture}
答案1
我得到了以下图片：
为此，我大大减少了您的代码，看看这对您是否有用。
\documentclass{article}
\usepackage{tikz}
\usetikzlibrary{arrows,backgrounds,calc,fit,matrix,positioning,
shapes,shapes.geometric,shapes.misc}
\pgfdeclarelayer{foreground}
\pgfdeclarelayer{background}
\pgfsetlayers{background,%
main,%
foreground%
}
\begin{document}
\begin{tikzpicture}[
venn circle/.style = {circle, draw, thick, fill=#1,
minimum width=9mm, opacity=0.6},
buffer/.style = {
isosceles triangle,
isosceles triangle apex angle=66,
shape border rotate=90,
fill=blue!20, opacity=0.6,
node distance=5cm,
rounded corners=60pt,
minimum height=6cm},
frames/.style args = {#1/#2}{minimum height=#1,
minimum width=#2+\pgfkeysvalueof{/pgf/minimum height},
draw, rounded corners=5mm, fill=yellow, opacity=0.6,
sloped},
]
\begin{pgfonlayer}{foreground}
\node (A) [venn circle = green] at (0,0) {A};
\node (B) [venn circle = green] at (-2,-3) {B};
\node (C) [venn circle = green] at (2,-3) {C};
\node (ABC) at (0,-2) {ABC};
\node (AB) at (-1,-1.5) {AB};
\node (AC) at (1,-1.5) {AC};
\node (BC) at (0,-3) {BC};
\end{pgfonlayer}
\begin{pgfonlayer}{main}
\path let \p1 = ($(C.center)-(A.center)$),
\n1 = {veclen(\y1,\x1)} in
(A) --
node[frames=11mm/\n1] {} (C);
\path let \p1 = ($(B.center)-(C.center)$),
\n1 = {veclen(\y1,\x1)} in
(B) --
node[frames=11mm/\n1] {} (C);
\end{pgfonlayer}
\begin{pgfonlayer}{background}
\node[buffer]at (0,-1.9){};
\end{pgfonlayer}
\end{tikzpicture}
\end{document}
编辑：在我的第一个版本中，我没有抓住问题的重点。感谢@Alenanno 指出这一点，我重新进行了回答（尽管这个问题可能是重复的......它至少是我的练习 :-)