patchcmd 和 double # 的问题

Question

gloss-greek.ldf我需要从( )修补以下宏polyglossia：

\def\greek@numbers{%
   \let\latin@alph\@alph%
   \let\latin@Alph\@Alph%
   \if@greek@numerals
      \def\greek@alph##1{\protect\greeknumber{##1}}%
      \def\greek@Alph##1{\protect\Greeknumber{##1}}%
      \let\@alph\greek@alph%
      \let\@Alph\greek@Alph%
   \fi}

到以下

\def\greek@numbers{%
   \let\latin@alph\@alph%
   \let\latin@Alph\@Alph%
   \if@greek@numerals
      \def\greek@alph##1{\protect\greeknumber{\the##1}}%
      \def\greek@Alph##1{\protect\Greeknumber{\the##1}}%
      \let\@alph\greek@alph%
      \let\@Alph\greek@Alph%
   \fi}

（添加两个\thes）。

然而我遇到了与# 的不同 catcode 相关的问题。

我尝试过修补宏内的参数但我至今都失败了。

工作示例：

\documentclass{memoir}

\usepackage{amsmath}
\usepackage{fontspec}
\usepackage{xpatch}

\usepackage{polyglossia}
\setdefaultlanguage{greek}
\setotherlanguage{english}
\newfontfamily\greekfont{Times New Roman}

\usepackage{xpatch}
\tracingpatches
\makeatletter
\newcommand{\patchme}{%
\xpatchcmd{\greek@numbers}{\greeknumber{##1}}{\greeknumber{\the##1}}{}{} 
\xpatchcmd{\greek@numbers}{\Greeknumber{##1}}{\Greeknumber{\the##1}}{}{}
}
\makeatother


\begin{document}
\patchme
\begin{subequations}
\begin{align}
a &= b \label{eq:eq1}\\
c &= d \label{eq:eq2}
\end{align}
\end{subequations}

This is \eqref{eq:eq2}? Is it really?

\end{document}

如果应用了补丁，引用将看起来正确。日志内容如下：

[debug] tracing \patchcmd on input line 28
[debug] analyzing '\greek@numbers'
[debug] ++ control sequence is defined
[debug] ++ control sequence is a macro
[debug] -- nested patching command and parameters in patch
[debug] -> the patching command seems to be nested in the
[debug] argument to some other command
[debug] -> the patch text seems to contain # characters
[debug] -> either avoid nesting or use # characters with
[debug] category code 12 in the patch text
[debug] -> simply doubling the # characters will not work

Answer 1

据我所知，使用##with etoolbox（内部使用）修补命令是不可能的。xpatch

我不确定为什么你需要\the在那个地方，因为有没有它输出都是一样的。无论如何，我更喜欢\number。

可以使用 进行修补regexpatch。 可以一次性完成所有修补，注意我们要用 替换每次出现的{##1}，{\number##1}因此我们可以使用\xpatchcmd*。

\documentclass{memoir}

\usepackage{amsmath}
\usepackage{fontspec}
\usepackage{regexpatch}

\usepackage{polyglossia}
\setdefaultlanguage{greek}
\setotherlanguage{english}
\newfontfamily\greekfont{Times New Roman}

\makeatletter
\xpatchcmd*{\greek@numbers}
  {{##1}}
  {{\number##1}}
  {\typeout{Hurray!}}{\typeout{Rats!}}
\makeatother

\begin{document}

\begin{subequations}
\begin{align}
a &= b \label{eq:eq1}\\
c &= d \label{eq:eq2}
\end{align}
\end{subequations}

This is \eqref{eq:eq2}? Is it really?

\end{document}

以下是终端输出的相关部分：

(/usr/local/texlive/2015/texmf-dist/tex/latex/polyglossia/gloss-english.ldf)
Hurray!
(./doublehash.aux) (/usr/local/texlive/2015/texmf-dist/tex/latex/tipa/t3cmr.fd)
[1] (./doublehash.aux) )
Output written on doublehash.pdf (1 page).

Answer 2

如果问题在于如何修复 MWE，那么可以通过避免使用 totally 来修复，而仅仅在序言中xpatch重新指定 total 所需的定义。\greek@numbers

\documentclass{memoir}

\usepackage{amsmath}
\usepackage{fontspec}

\usepackage{polyglossia}
\setdefaultlanguage{greek}
\setotherlanguage{english}
\newfontfamily\greekfont{Times New Roman}

\makeatletter
\def\greek@numbers{%
   \let\latin@alph\@alph%
   \let\latin@Alph\@Alph%
   \if@greek@numerals
      \def\greek@alph##1{\protect\greeknumber{\the##1}}%
      \def\greek@Alph##1{\protect\Greeknumber{\the##1}}%
      \let\@alph\greek@alph%
      \let\@Alph\greek@Alph%
   \fi}
\makeatother


\begin{document}
\begin{subequations}
\begin{align}
a &= b \label{eq:eq1}\\
c &= d \label{eq:eq2}
\end{align}
\end{subequations}

This is \eqref{eq:eq2}? Is it really?

\end{document}

然而，如果 OP 问题的真正目的是了解其论点中为什么\xpatchcmd不喜欢的本质##1，那么这个答案就没有任何意义。

##1下面是一个更简单的 MWE，用于在宏中演示 的问题\xpatchcmd。如果补丁有效，结果将是Q(C)，而不是B(C)。

\documentclass{article}
\usepackage{xpatch}
\def\A{\def\B##1{B({##1})}}
\xpatchcmd{\A}{B({##1})}{Q({##1})}{\xdef\result{successful}}{\xdef\result{unsuccessful}} 
\A
\begin{document}
\B{C}.  Patch was \result.
\end{document}