是否可以格式化表格，使一列中的文本分布在多行中，且文本从下到上垂直显示，或从上到下垂直显示？在这种情况下，给定应该是该列并且文本大小应该适合几行跨度。
\begin{center}
\begin{tabular}{r|c|r|r|l|l|l|r|l}
\multicolumn{1}{c|}{$i$} & class & \multicolumn{1}{c|}{$x_i$} & \multicolumn{1}{c|}{$f_i$} & \multicolumn{1}{c|}{$f_{r_i} = \frac{f_i}{n+1}$} & \multicolumn{1}{c|}{$\Phi_i = \sum\limits_{i=1} f_{r_i}$} & \multicolumn{1}{c|}{$f_{tr_i}$} & \multicolumn{1}{c|}{$f_{t_i} = n \cdot f_{tr_i}$} & \multicolumn{1}{c}{$F_i = \sum\limits_{i=1} f_{tr_i}$} \\\hline
1 & 14–18 & 16 & 28 & & & given & 27,7 & \\
2 & 18–22 & 20 & 18 & & & given & 18,3 & \\
3 & 22–26 & 24 & 11 & & & given & 11,05 & \\
4 & 26–30 & 28 & 9 & & & given & 6,5 & \\
5 & 30–34 & 32 & 2 & & & given & 3,8 & \\
6 & 34–38 & 36 & 2 & & & given & 2,2 & \\
7 & 38–42 & 40 & 0 & & & given & 1,9 & \\
8 & 42–46 & 44 & 1 & & & given & 0,7 & \\
9 & 46–50 & 48 & 1 & & & given & 0,43 & \\
10 & 50–52 & 52 & 1 & & & given & 0,24 &
\end{tabular}
\end{center}
或者这里，如何跨越文本给定，再次，最好使用大一点的字体，并分成几列？
\begin{center}
\begin{tabular}{c|cccccc}
T & 2 & 5 & 10 & 25 & 50 & 100 \\ \hline
$x_T$ & given & given & given & given & given & given \\
$x'_T$ & & & & & & \\
$x''_T$ & & & & & & \\
$\displaystyle\frac{B}{\sqrt{n}}$ & given & given & given & given & given & given
\end{tabular}
\end{center}
太感谢了！
答案1
也许是这样的？
\documentclass{article}
\usepackage{multirow, rotating, graphicx}
\usepackage{siunitx, makecell, bigstrut}
\begin{document}
\begin{center}
\sisetup{table-format=2.2, output-decimal-marker={,}}
\setcellgapes{2pt}\makegapedcells
\begin{tabular}{r|c|r|r|l|c|l|S|l}
\multicolumn{1}{c|}{$i$} & class & \multicolumn{1}{c|}{$x_i$} & \multicolumn{1}{c|}{$f_i$} & \multicolumn{1}{c|}{$f_{r_i} = \frac{f_i}{n+1}$} & \multicolumn{1}{c|}{$\Phi_i = \sum\limits_{i=1} f_{r_i}$} & \multicolumn{1}{c|}{$f_{tr_i}$} & \bigstrut{$f_{t_i} = n \cdot f_{tr_i}$} & \multicolumn{1}{c}{$F_i = \sum\limits_{i=1} f_{tr_i}$} \\\hline
\bigstrut[t] 1 & 14–18 & 16 & 28 & & & \multirow{11}{*}{\Large \hspace{0.2ex}\rotatebox{90}{given}} & 27,7 & \\%
2 & 18–22 & 20 & 18 & & & & 18,3 & \\
3 & 22–26 & 24 & 11 & & & & 11,05 & \\
4 & 26–30 & 28 & 9 & & & & 6,5 & \\
5 & 30–34 & 32 & 2 & & & & 3,8 & \\
6 & 34–38 & 36 & 2 & & & & 2,2 & \\
7 & 38–42 & 40 & 0 & & & & 1,9 & \\
8 & 42–46 & 44 & 1 & & & & 0,7 & \\
9 & 46–50 & 48 & 1 & & & & 0,43 & \\
10 & 50–52 & 52 & 1 & & & & 0,24 &
\end{tabular}
\end{center}
\end{document}
答案2
伯纳德，非常感谢！
以下是我最终做的事情：
\begin{center}
\sisetup{table-format=2.2, output-decimal-marker={,}}
\setcellgapes{2pt}\makegapedcells
\begin{tabular}{rcrrlclSl}
\multicolumn{1}{c}{$i$} & classes & \multicolumn{1}{c}{$x_i$} & \multicolumn{1}{c}{$f_i$} & \multicolumn{1}{c}{${\scriptstyle f_{r_i} = \frac{f_i}{n+1}}$} & \multicolumn{1}{c}{${\scriptstyle\Phi_i = \sum\limits_{i=1} f_{r_i}}$} & \multicolumn{1}{c}{$f_{tr_i}$} & \bigstrut{${\scriptstyle f_{t_i} = n \cdot f_{tr_i}}$} & \multicolumn{1}{c}{${\scriptstyle F_i = \sum\limits_{i=1} f_{tr_i}}$} \\\midrule
\bigstrut[t] 1 & 14–18 & 16 & 28 & & \multirow{11}{*}{ \hspace{0.2ex}\rotatebox{90}{not wanted}} & \multirow{11}{*}{ \hspace{0.2ex}\rotatebox{90}{Scientific WorkPlace}} & 27,7 & \multirow{11}{*}{\hspace{0.2ex}\rotatebox{90}{not wanted}}\\%
2 & 18–22 & 20 & 18 & & & & 18,3 & \\
3 & 22–26 & 24 & 11 & & & & 11,05 & \\
4 & 26–30 & 28 & 9 & & & & 6,5 & \\
5 & 30–34 & 32 & 2 & & & & 3,8 & \\
6 & 34–38 & 36 & 2 & & & & 2,2 & \\
7 & 38–42 & 40 & 0 & & & & 1,9 & \\
8 & 42–46 & 44 & 1 & & & & 0,7 & \\
9 & 46–50 & 48 & 1 & & & & 0,43 & \\
10 & 50–52 & 52 & 1 & & & & 0,24 &
\end{表格} \end{中心}
不过，我似乎无法将文本置于最后一列的中心。
你知道我做错什么了吗？