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图形放置不完美

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图形放置不完美

迷你页面部分排列不正确

在上面的链接中我找到了最有用的答案。我问了一个新问题，我遇到了一个问题，即第二部分中的图被拖下来了，我不明白这是怎么回事？

代碼：

\documentclass[12pt, a4paper]{article}
\usepackage[
top=0.6in,bottom=0.5in,left=0.7in,right=0.5in]{geometry}
\usepackage[utf8]{inputenc}
\usepackage[misc]{ifsym}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{mathtools}
\usepackage{amssymb}
\usepackage{forest}
\usepackage{subcaption}
\usepackage[parfill]{parskip}
%line spacing
\renewcommand{\baselinestretch}{0.9}
\usepackage{tikz}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usetikzlibrary{intersections}
\headsep=10pt

\usepackage{wrapfig}
\begin{document}
    \begin{wrapfigure}{r}{6cm}
        \centering
        \begin{tikzpicture}
        %\draw[step=1cm,red,very thin] (-4,-4) grid (11,7);
        \tkzDefPoint(2,3.5){P}
        \tkzDefPoint(0,0){Q}
        \tkzDefPoint(4,0){R}
        \tkzDefPoint(0.8,1.4){E}
        \tkzDefPoint(2.6,2.4){F}
        \tkzDrawSegments(P,Q Q,R P,R E,F)
        \tkzLabelPoints[above,yshift=0pt](P)
        \tkzLabelPoints[left,yshift=4pt](Q)
        \tkzLabelPoints[right,yshift=4pt](R)
        \tkzLabelPoints[left,xshift=0pt](E)
        \tkzLabelPoints[right,xshift=00pt](F)
        \end{tikzpicture}
    \end{wrapfigure}

    For (i)
    \begin{align*}
    \dfrac{PE}{EQ}&=\dfrac{3.9}{3}=1.3\\
    \dfrac{PF}{FR}&=\dfrac{3.6}{2.4}=1.5\\
    \dfrac{PE}{EQ}&\neq \dfrac{PF}{FR}
    \end{align*}
    Therefore, $EF$ is not parallel to $QR$.

    \begin{wrapfigure}{r}{6cm}
        \centering
        \begin{tikzpicture}
        \tkzDefPoint(2,3.5){P}
        \tkzDefPoint(0,0){Q}
        \tkzDefPoint(4,0){R}
        \tkzDefPoint(0.8,1.4){E}
        \tkzDefPoint(3.2,1.4){F}
        \tkzDrawSegments(P,Q Q,R P,R E,F)
        \tkzLabelPoints[above,yshift=0pt](P)
        \tkzLabelPoints[left,yshift=4pt](Q)
        \tkzLabelPoints[right,yshift=4pt](R)
        \tkzLabelPoints[left,xshift=0pt](E)
        \tkzLabelPoints[right,xshift=00pt](F)
        \end{tikzpicture}
    \end{wrapfigure}
    For (ii)
    \begin{align*}
    \dfrac{PE}{QE}&=\dfrac{4}{4.5}=\dfrac{8}{9}\\
    \dfrac{PF}{RF}&=\dfrac{8}{9}\\
    \dfrac{PE}{QE}&=\dfrac{PF}{RF}
    \end{align*}
    Therefore, $EF$ is not parallel to $QR$.
\end{document}

答案1

如果您添加一些 Lipsum 文本，您将看到wrapfigure在第一个数字下方产生很大的空间（叹气）。但是，您可以通过添加一个选项来消除这个空间，[5]这意味着该图形的高度将只有 5 行文本的高度（请注意，这些行可能非常宽，就像分数一样）

\documentclass[12pt, a4paper]{article}
\usepackage[
top=0.6in,bottom=0.5in,left=0.7in,right=0.5in]{geometry}
\usepackage[utf8]{inputenc}
\usepackage[misc]{ifsym}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{mathtools}
\usepackage{amssymb}
\usepackage{forest}
\usepackage{subcaption}
\usepackage[parfill]{parskip}
%line spacing
\renewcommand{\baselinestretch}{0.9}
\usepackage{tikz}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usetikzlibrary{intersections}
\headsep=10pt

\usepackage{wrapfig}
\usepackage{lipsum}
\begin{document}
    \begin{wrapfigure}[5]{r}{6cm} % <=================================
        \centering
        \begin{tikzpicture}
        %\draw[step=1cm,red,very thin] (-4,-4) grid (11,7);
        \tkzDefPoint(2,3.5){P}
        \tkzDefPoint(0,0){Q}
        \tkzDefPoint(4,0){R}
        \tkzDefPoint(0.8,1.4){E}
        \tkzDefPoint(2.6,2.4){F}
        \tkzDrawSegments(P,Q Q,R P,R E,F)
        \tkzLabelPoints[above,yshift=0pt](P)
        \tkzLabelPoints[left,yshift=4pt](Q)
        \tkzLabelPoints[right,yshift=4pt](R)
        \tkzLabelPoints[left,xshift=0pt](E)
        \tkzLabelPoints[right,xshift=00pt](F)
        \end{tikzpicture}
    \end{wrapfigure}

    For (i)
    \begin{align*}
    \dfrac{PE}{EQ}&=\dfrac{3.9}{3}=1.3\\
    \dfrac{PF}{FR}&=\dfrac{3.6}{2.4}=1.5\\
    \dfrac{PE}{EQ}&\neq \dfrac{PF}{FR}
    \end{align*}
    Therefore, $EF$ is not parallel to $QR$.

    \begin{wrapfigure}{r}{6cm}
        \centering
        \begin{tikzpicture}
        \tkzDefPoint(2,3.5){P}
        \tkzDefPoint(0,0){Q}
        \tkzDefPoint(4,0){R}
        \tkzDefPoint(0.8,1.4){E}
        \tkzDefPoint(3.2,1.4){F}
        \tkzDrawSegments(P,Q Q,R P,R E,F)
        \tkzLabelPoints[above,yshift=0pt](P)
        \tkzLabelPoints[left,yshift=4pt](Q)
        \tkzLabelPoints[right,yshift=4pt](R)
        \tkzLabelPoints[left,xshift=0pt](E)
        \tkzLabelPoints[right,xshift=00pt](F)
        \end{tikzpicture}
    \end{wrapfigure}

    For (ii)
    \begin{align*}
    \dfrac{PE}{QE}&=\dfrac{4}{4.5}=\dfrac{8}{9}\\
    \dfrac{PF}{RF}&=\dfrac{8}{9}\\
    \dfrac{PE}{QE}&=\dfrac{PF}{RF}
    \end{align*}
    Therefore, $EF$ is not parallel to $QR$.
\end{document}

在此处输入图片描述

答案2

使用小页面：

\documentclass[12pt, a4paper]{article}
\usepackage[
top=0.6in,bottom=0.5in,left=0.7in,right=0.5in]{geometry}
\usepackage[utf8]{inputenc}
\usepackage[misc]{ifsym}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{mathtools}
\usepackage{amssymb}
\usepackage{forest}
\usepackage{subcaption}
\usepackage[parfill]{parskip}
%line spacing
\renewcommand{\baselinestretch}{0.9}
\usepackage{tikz}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usetikzlibrary{intersections}
\headsep=10pt

\usepackage{wrapfig}
\begin{document}

\begin{minipage}{\textwidth-6cm}
    For (i)
    \begin{align*}
    \dfrac{PE}{EQ}&=\dfrac{3.9}{3}=1.3\\
    \dfrac{PF}{FR}&=\dfrac{3.6}{2.4}=1.5\\
    \dfrac{PE}{EQ}&\neq \dfrac{PF}{FR}
    \end{align*}
    Therefore, $EF$ is not parallel to $QR$.
\end{minipage}%
\begin{minipage}{6cm}
        \centering
        \begin{tikzpicture}
        %\draw[step=1cm,red,very thin] (-4,-4) grid (11,7);
        \tkzDefPoint(2,3.5){P}
        \tkzDefPoint(0,0){Q}
        \tkzDefPoint(4,0){R}
        \tkzDefPoint(0.8,1.4){E}
        \tkzDefPoint(2.6,2.4){F}
        \tkzDrawSegments(P,Q Q,R P,R E,F)
        \tkzLabelPoints[above,yshift=0pt](P)
        \tkzLabelPoints[left,yshift=4pt](Q)
        \tkzLabelPoints[right,yshift=4pt](R)
        \tkzLabelPoints[left,xshift=0pt](E)
        \tkzLabelPoints[right,xshift=00pt](F)
        \end{tikzpicture}
\end{minipage}



    \bigskip
\begin{minipage}{\textwidth-6cm}
    For (ii)
    \begin{align*}
    \dfrac{PE}{QE}&=\dfrac{4}{4.5}=\dfrac{8}{9}\\
    \dfrac{PF}{RF}&=\dfrac{8}{9}\\
    \dfrac{PE}{QE}&=\dfrac{PF}{RF}
    \end{align*}
    Therefore, $EF$ is not parallel to $QR$.
\end{minipage}%
\begin{minipage}{6cm}
        \centering
        \begin{tikzpicture}
        \tkzDefPoint(2,3.5){P}
        \tkzDefPoint(0,0){Q}
        \tkzDefPoint(4,0){R}
        \tkzDefPoint(0.8,1.4){E}
        \tkzDefPoint(3.2,1.4){F}
        \tkzDrawSegments(P,Q Q,R P,R E,F)
        \tkzLabelPoints[above,yshift=0pt](P)
        \tkzLabelPoints[left,yshift=4pt](Q)
        \tkzLabelPoints[right,yshift=4pt](R)
        \tkzLabelPoints[left,xshift=0pt](E)
        \tkzLabelPoints[right,xshift=00pt](F)
        \end{tikzpicture}
\end{minipage}

\end{document}

您还可以使用paracol如下所示的包：

\documentclass[12pt, a4paper]{article}
\usepackage[
top=0.6in,bottom=0.5in,left=0.7in,right=0.5in]{geometry}
\usepackage[utf8]{inputenc}
\usepackage[misc]{ifsym}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{mathtools}
\usepackage{amssymb}
\usepackage{forest}
\usepackage{subcaption}
\usepackage[parfill]{parskip}
%line spacing
\renewcommand{\baselinestretch}{0.9}
\usepackage{tikz}
\usepackage{tkz-euclide}
\usetkzobj{all}
\usetikzlibrary{intersections}
\headsep=10pt

\usepackage{paracol}

\begin{document}
\begin{paracol}{2}
    For (i)
    \begin{align*}
    \dfrac{PE}{EQ}&=\dfrac{3.9}{3}=1.3\\
    \dfrac{PF}{FR}&=\dfrac{3.6}{2.4}=1.5\\
    \dfrac{PE}{EQ}&\neq \dfrac{PF}{FR}
    \end{align*}
    Therefore, $EF$ is not parallel to $QR$.
\switchcolumn
        {\centering
        \begin{tikzpicture}
        %\draw[step=1cm,red,very thin] (-4,-4) grid (11,7);
        \tkzDefPoint(2,3.5){P}
        \tkzDefPoint(0,0){Q}
        \tkzDefPoint(4,0){R}
        \tkzDefPoint(0.8,1.4){E}
        \tkzDefPoint(2.6,2.4){F}
        \tkzDrawSegments(P,Q Q,R P,R E,F)
        \tkzLabelPoints[above,yshift=0pt](P)
        \tkzLabelPoints[left,yshift=4pt](Q)
        \tkzLabelPoints[right,yshift=4pt](R)
        \tkzLabelPoints[left,xshift=0pt](E)
        \tkzLabelPoints[right,xshift=00pt](F)
        \end{tikzpicture}}
\switchcolumn
    For (ii)
    \begin{align*}
    \dfrac{PE}{QE}&=\dfrac{4}{4.5}=\dfrac{8}{9}\\
    \dfrac{PF}{RF}&=\dfrac{8}{9}\\
    \dfrac{PE}{QE}&=\dfrac{PF}{RF}
    \end{align*}
    Therefore, $EF$ is not parallel to $QR$.
\switchcolumn
       { \centering
        \begin{tikzpicture}
        \tkzDefPoint(2,3.5){P}
        \tkzDefPoint(0,0){Q}
        \tkzDefPoint(4,0){R}
        \tkzDefPoint(0.8,1.4){E}
        \tkzDefPoint(3.2,1.4){F}
        \tkzDrawSegments(P,Q Q,R P,R E,F)
        \tkzLabelPoints[above,yshift=0pt](P)
        \tkzLabelPoints[left,yshift=4pt](Q)
        \tkzLabelPoints[right,yshift=4pt](R)
        \tkzLabelPoints[left,xshift=0pt](E)
        \tkzLabelPoints[right,xshift=00pt](F)
        \end{tikzpicture}}
\end{paracol}

\end{document}

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