tikz计算维度太大x的平方

Question

我想对带有可变半径圆的图表上的坐标进行广泛的三角计算。太快了，半径值为 5，我得到了“尺寸太大”的错误。这是我的 MWE：

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usetikzlibrary{math, calc, fpu}
\title{MWE}

\begin{document}
\begin{tikzpicture}
\def\angleTheta{180}
\def\r{5}

\node (C) at (0,0) {C};

\draw  ($(C) + (0:{\r})$) arc (0:\angleTheta:\r);

\pgfgetlastxy{\xb}{\yb}
\node at (-\r,-1) {xb=\xb};
\node at (-\r,-2) {yb=\yb};

\tikzmath{\carre= \xb*\xb;}  

\pgfmathsetmacro\rayon{sqrt(\xb*\xb +\yb*\yb)}

\tikzmath{\rayon= sqrt(\xb*\xb +\yb*\yb);}  

\node at (-\r,-3) {rayon=\rayon};


\end{tikzpicture}
\end{document}

Answer 1

您可以xfp改用用于计算大数的包：

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usepackage{xfp}
\usetikzlibrary{math, calc, fpu}
\title{MWE}

\begin{document}
\begin{tikzpicture}
\def\angleTheta{180}
\def\r{5}

\node (C) at (0,0) {C};

\draw  ($(C) + (0:{\r})$) arc (0:\angleTheta:\r);

\pgfgetlastxy{\xb}{\yb}
\node at (-\r,-1) {xb=\xb};
\node at (-\r,-2) {yb=\yb};

\edef\carre{\fpeval{\xb*\xb}pt}

\edef\rayon{\fpeval{sqrt(\xb*\xb + \yb*\yb)}pt}

\node at (-\r,-3) {rayon=\rayon};


\end{tikzpicture}
\end{document}

您还可以使用fpuTi钾Z，但必须激活：

\documentclass{article}
\usepackage[utf8]{inputenc}
\usepackage{tikz}
\usetikzlibrary{math, calc, fpu}
\title{MWE}

\begin{document}
\begin{tikzpicture}
\def\angleTheta{180}
\def\r{5}

\node (C) at (0,0) {C};

\draw  ($(C) + (0:{\r})$) arc (0:\angleTheta:\r);

\pgfgetlastxy{\xb}{\yb}
\node at (-\r,-1) {xb=\xb};
\node at (-\r,-2) {yb=\yb};

\pgfset{fpu=true,fpu/output format=fixed}
\tikzmath{\carre= \xb*\xb;}  

\pgfmathsetmacro\rayon{sqrt(\xb*\xb +\yb*\yb)}

\tikzmath{\rayon= sqrt(\xb*\xb +\yb*\yb);}  
\pgfset{fpu=false} % hopefully this fixes the issues of github.com/pgf-tikz/pgf/issues/678

\node at (-\r,-3) {rayon=\rayon pt};


\end{tikzpicture}
\end{document}

Answer 2

使用let操作。

\documentclass{article}
\pagestyle{empty}
\usepackage{tikz}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}
\def\angleTheta{180}
\def\r{5}

\node (C) at (0,0) {C};
\draw ($(C) + (0:{\r})$) arc (0:\angleTheta:\r) coordinate (ref);
\path let \p1=(ref),
          %\n{carre}={\x1*\x1},
          \n{rayon}={veclen(\x1,\y1)}
    in 
        node at (-\r,-1) {xb=\x1}
        node at (-\r,-2) {yb=\y1}
        node at (-\r,-3) {rayon=\n{rayon}};

\end{tikzpicture}
\end{document}