矩阵并排排列，中间有列分隔符

Question

我的问题是使用 LaTeX 获得以下输出。我正在使用文章与...类数学包。我当然可以得到矩阵，但得不到图像中显示的形式。任何帮助完成这项工作的帮助都将不胜感激。

Answer 1

一个选择是nicematrix。

\documentclass{article}
\usepackage{geometry}
\usepackage{mathtools}
\usepackage{nicematrix}
\begin{document}
\begin{align*}
  E_1&=
  \begin{bNiceArray}{rrr}[first-row,last-col]
\multicolumn{3}{c}{\mathclap{\textcolor{magenta}{\text{Elementary Matrix}}}}\\
        0 & 1 & 0 &\textcolor{magenta}{R_1\leftrightarrow R_2}\\
        1 & 0 & 0 & \\
        0 & 0 & 1 & \\
  \end{bNiceArray}
  &
  E_1^{-1}&=
  \begin{bNiceArray}{rrr}[first-row,last-col]
\multicolumn{3}{c}{\mathclap{\textcolor{magenta}{\text{Inverse Matrix}}}}\\
        0 & 1 & 0 &\textcolor{magenta}{R_1\leftrightarrow R_2}\\
        1 & 0 & 0 & \\
        0 & 0 & 1 & \\
  \end{bNiceArray}\\
  E_2&=
  \begin{bNiceArray}{rrr}[last-col]
        1 & 0 & 0 &\\
        0 & 1 & 0 & \\
        -2 & 0 & 1&
        \textcolor{magenta}{R_2+(-2)R_1\to R_3} \\
  \end{bNiceArray} 
  &
  E_2^{-1}&=
  \begin{bNiceArray}{rrr}[last-col]
        1 & 0 & 0 &\\
        0 & 1 & 0 & \\
        2 & 0 & 1 & \textcolor{magenta}{R_2+(2)R_1\to R_3} \\
 \end{bNiceArray}  \\
  E_3&=
  \begin{bNiceArray}{rrr}[last-col]
        1 & 0 & 0 &\\
        0 & 1 & 0 & \\
        0 & 0 & \frac{1}{2} &
        \textcolor{magenta}{(\tfrac{1}{2})R_3\to R_3} \\
  \end{bNiceArray} 
  &
  E_3^{-1}&=
  \begin{bNiceArray}{rrr}[last-col]
        1 & 0 & 0 &\\
        0 & 1 & 0 & \\
        0 & 0 & 2 & \textcolor{magenta}{(2)R_3\to R_3} 
  \end{bNiceArray} \\
\end{align*}
\end{document}

另一个选择是blkarray。

\documentclass{article}
\usepackage{geometry}
\usepackage{amsmath}
\usepackage{blkarray}
\usepackage{bigstrut}
\usepackage{xcolor}
\begin{document}
\begin{align*}
  E_1&=
  \begin{array}{@{}l@{}}
  \textcolor{magenta}{\text{Elementary Matrix}}\\
  \begin{blockarray}{[rrr]l}
        \bigstrut[t]0 & 1 & 0 &\textcolor{magenta}{R_1\leftrightarrow R_2}\\
        1 & 0 & 0 & \\
        0 & 0 & 1 & \\
  \end{blockarray} 
  \end{array}
  &
  E_1^{-1}&=
  \begin{array}{@{}l@{}}
  \textcolor{magenta}{\text{Inverse Matrix}}\\
  \begin{blockarray}{[rrr]l}
        \bigstrut[t]0 & 1 & 0 &\textcolor{magenta}{R_1\leftrightarrow R_2}\\
        1 & 0 & 0 & \\
        0 & 0 & 1 & \\
  \end{blockarray}
  \end{array} \\
  E_2&=
  \begin{blockarray}[t]{[rrr]l}
        1 & 0 & 0 \bigstrut[t]&\\
        0 & 1 & 0 & \\
        -2 & 0 & 1&
        \textcolor{magenta}{R_2+(-2)R_1\to R_3} 
  \end{blockarray} 
  &
  E_2^{-1}&=
  \begin{blockarray}[t]{[rrr]l}
        \bigstrut[t]1 & 0 & 0 &\\
        0 & 1 & 0 & \\
        2 & 0 & 1 & \textcolor{magenta}{R_2+(2)R_1\to R_3} \\
  \end{blockarray} \\
  E_3&=
  \begin{blockarray}[t]{[rrr]l}
        \bigstrut[t]1 & 0 & 0 &\\
        0 & 1 & 0 & \\
        0 & 0 & \frac{1}{2} &
        \textcolor{magenta}{(\tfrac{1}{2})R_3\to R_3} \\
  \end{blockarray} 
  &
  E_3^{-1}&=
  \begin{blockarray}[t]{[rrr]l}
        \bigstrut[t]1 & 0 & 0 &\\
        0 & 1 & 0 & \\
        0 & 0 & 2 & \textcolor{magenta}{(2)R_3\to R_3} 
  \end{blockarray} \\
\end{align*}
\end{document}