我想要一个贝叶斯博弈论问题的概率树,它看起来完全像这样:
这是我尝试编写的代码
*编辑一个更清晰的序言
\documentclass[12pt, a4 paper]{article}
\usepackage{multicol} %Needed for \PDgame
\usepackage{multirow}
\usepackage{wrapfig}
\usepackage{tabu}
\usepackage{mathtools}
\usepackage{graphicx}
\usepackage[english]{babel}
\usepackage[utf8]{inputenc}
\usepackage{amsmath,amssymb}
\usepackage{parskip}
\usepackage{graphicx}
\usepackage{tabu}
\usepackage{mathtools}
\usepackage{graphicx}
\usepackage{verbatim}
\usepackage{subcaption}
\usepackage{indentfirst}
\usepackage{tikz}
% Margins
\usepackage[inner=2.0cm,outer=2.0cm,top=2.5cm,bottom=2.5cm]{geometry}
% Colour table cells
\usepackage[table]{xcolor}
\setlength{\marginparwidth}{2cm}
\begin{document}
A FAILED ATTEMPT TO MAKE THE PROB TREE WITH JUST ONE TABLE
\begin{center}
\begin{tikzpicture}
\node(0){root}
child{node{child 1}
child{node{
\begin{tabular}{cc|c|c|c|}
& \multicolumn{2}{c}{$Pr(\omega_1)=\frac{1}{2}$}&
\multicolumn2c{\color{blue}Player 2} \\
& \multicolumn2c{} & \multicolumn1c{$p$} & \multicolumn1c{$1-p$} \\
\cline{3-5}
&&& $a_2$ & $b_2$ \\
\cline{3-5}
\multirow2*{\color{red}Player 1} &$q$ & $a_1$
& $\textbf{(\color{red}{0}\color{black}, \color{blue}
{0}\color{black})}$
& $(\color{red}{6}\color{black}, \color{blue}{-3}\color{black})$ \\
\cline{3-5}
& $1 - q$ & $b_1$
& $(\color{red}{-3} \color{black}, \color{blue}{6}\color{black})$
& $(\color{red}{5} \color{black}, \color{blue}{5}\color{black})$ \\
\cline{3-5}
\end{tabular}
}}
}
child{node{child 2}
}
;
\end{tikzpicture}
\end{center}
CODE OF THE TABLES NEEDED IN THE NODES
TABLE 1
\begin{center}
\begin{tabular}{cc|c|c|c|}
& \multicolumn{2}{c}{$Pr(\omega_1)=\frac{1}{2}$} &
\multicolumn2c{\color{blue}Player 2} \\
& \multicolumn2c{} & \multicolumn1c{$p$} & \multicolumn1c{$1-p$} \\
\cline{3-5}
&&& $a_2$ & $b_2$ \\
\cline{3-5}
\multirow2*{\color{red}Player 1} &$q$ & $a_1$
& $\textbf{(\color{red}{0}\color{black}, \color{blue}
{0}\color{black})}$
& $(\color{red}{6}\color{black}, \color{blue}{-3}\color{black})$ \\
\cline{3-5}
& $1 - q$ & $b_1$
& $(\color{red}{-3} \color{black}, \color{blue}{6}\color{black})$
& $(\color{red}{5} \color{black}, \color{blue}{5}\color{black})$ \\
\cline{3-5}
\end{tabular}
\end{center}
and
TABLE 2
\begin{center}
\begin{tabular}{cc|c|c|c|}
& \multicolumn{2}{c}{$Pr(\omega_1)=\frac{1}{2}$} &
\multicolumn2c{\color{blue}Player 2} \\
& \multicolumn2c{} & \multicolumn1c{$p$} & \multicolumn1c{$1-p$} \\
\cline{3-5}
&&& $a_2$ & $b_2$ \\
\cline{3-5}
\multirow2*{\color{red}Player 1} &$q$ & $a_1$
& $\textbf{(\color{red}{-20}\color{black}, \color{blue}
{-20}\color{black})}$
& $(\color{red}{-7}\color{black}, \color{blue}{-16}\color{black})$
\\
\cline{3-5}
& $1 - q$ & $b_1$
& $(\color{red}{-16} \color{black}, \color{blue}{-7}\color{black})$
& $(\color{red}{-5} \color{black}, \color{blue}{-5}\color{black})$
\\
\cline{3-5}
\end{tabular}
\end{center}
\end{document}
答案1
起点:
\documentclass[12pt, a4paper]{article}
\usepackage{multirow} \usepackage[table]{xcolor} \usepackage{tikz} \usepackage[inner=2.0cm,outer=2.0cm,top=2.5cm,bottom=2.5cm]{geometry} \setlength{\marginparwidth}{2cm} \begin{document}
\begin{center} \small \setlength{\tabcolsep}{5pt} \begin{tikzpicture}[level distance=2cm,sibling distance=8.5cm] \node(0){Z}
child{node{
\begin{tabular}{cc|c|c|c|}
& \multicolumn{2}{c}{$Pr(\omega_1)=\frac{1}{2}$}& \multicolumn2c{\color{blue}Player 2} \\
& \multicolumn{2}{c}{} & \multicolumn{1}{c}{$p$} & \multicolumn{1}{c}{$1-p$} \\
\cline{3-5}
&&& $a_2$ & $b_2$ \\
\cline{3-5}
\multirow2*{\color{red}Player 1} &$q$ & $a_1$
& $\textbf{(\color{red}{0}\color{black}, \color{blue} {0}\color{black})}$
& $(\color{red}{6}\color{black}, \color{blue}{-3}\color{black})$ \\
\cline{3-5}
& $1 - q$ & $b_1$
& $(\color{red}{-3} \color{black}, \color{blue}{6}\color{black})$
& $(\color{red}{5} \color{black}, \color{blue}{5}\color{black})$ \\
\cline{3-5}
\end{tabular}
}} child{node{ \begin{tabular}{cc|c|c|c|}
& \multicolumn{2}{c}{$Pr(\omega_1)=\frac{1}{2}$} & \multicolumn2c{\color{blue}Player 2} \\
& \multicolumn{2}{c}{} & \multicolumn{1}{c}{$p$} & \multicolumn{1}{c}{$1-p$} \\
\cline{3-5}
&&& $a_2$ & $b_2$ \\
\cline{3-5}
\multirow2*{\color{red}Player 1} &$q$ & $a_1$
& $\textbf{(\color{red}{-20}\color{black}, \color{blue} {-20}\color{black})}$
& $(\color{red}{-7}\color{black}, \color{blue}{-16}\color{black})$ \\
\cline{3-5}
& $1 - q$ & $b_1$
& $(\color{red}{-16} \color{black}, \color{blue}{-7}\color{black})$
& $(\color{red}{-5} \color{black}, \color{blue}{-5}\color{black})$ \\
\cline{3-5}
\end{tabular}} } ; \end{tikzpicture} \end{center}
\end{document}
答案2
附带forest
包装:
\documentclass[12pt]{article}
\usepackage[hmargin=2.0cm, vmargin=2.5cm,
marginparwidth=2cm]{geometry}
\usepackage{makecell, multirow}
\NewExpandableDocumentCommand\mcc{O{1}m}%
{\multicolumn{#1}{c}{#2}}
\usepackage[table]{xcolor}
\usepackage{forest}
\begin{document}
\begin{center}
\newcommand\B[1]{\textcolor{blue}{#1}}
\newcommand\R[1]{\textcolor{red}{#1}}
\setcellgapes{3pt}
\makegapedcells
\small
\setlength{\tabcolsep}{3pt}
\begin{forest}
for tree = {
% where level=1{draw=gray, dashed}{},
child anchor=north,
l sep=15mm,
s sep=2mm
}
[Z,
[{\begin{tabular}{@{} cc|c|c|c|}
\mcc[2]{$Pr(\omega_1)=\frac{1}{2}$}
&\mcc{} & \mcc[2]{\B{Player 2}} \\
\cline{4-5}
\mcc[2]{} & & $p$ & $1-p$ \\
\cline{4-5}
\mcc[2]{} & & $a_2$ & $b_2$ \\
\cline{3-5}
\multirow{2}{*}{\R{Player 1}}
& $q$ & $a_1$ & (\R{0},\B{0}) & (\R{6},\B{-3}) \\
\cline{3-5}
& $1-q$ & $b_1$ & (\R{-3},\B{6})& (\R{5},\B{5}) \\
\cline{3-5}
\end{tabular}},
edge label={node[pos=0.6,anchor=south east]{$\omega_1$}}]
[{\begin{tabular}{@{} cc|c|c|c|}
\mcc[2]{$Pr(\omega_2)=\frac{1}{2}$}
&\mcc{} & \mcc[2]{\B{Player 2}} \\
\cline{4-5}
\mcc[2]{} & & $p$ & $1-p$ \\
\cline{4-5}
\mcc[2]{} & & $a_2$ & $b_2$ \\
\cline{3-5}
\multirow{2}{*}{\R{Player 1}}
& $q$ & $a_1$ & (\R{-20},\B{-20}) & (\R{-7},\B{-16}) \\
\cline{3-5}
& $1-q$ & $b_1$ & (\R{-16},\B{-7}) & (\R{-5},\B{-5}) \\
\cline{3-5}
\end{tabular}},xshift=-2em,
edge label={node[pos=0.6,anchor=south west]{$\omega_2$}}]
]
\end{forest}
\end{center}
\end{document}