答案1
这是第一个电路,我将把第二个电路留给读者作为练习:)。
\documentclass[border=20, tikz]{standalone}
\usepackage{circuitikz}
\usetikzlibrary{calc}
\begin{document}
\begin{tikzpicture}
\draw (0, 0) to[L, l=\(L_1\)] (0, 4);
\draw (2, 0) to[C, l=\(C_1\), *-*] (2, 4);
\draw (2, 4) to[R, l=\(R_1\), *-*] (4, 4);
\draw (4, 0) to[C, l=\(C_2\), *-*] (4, 4);
\draw (6, 0) to[R, l=\(R_2\), *-] (6, 2);
\draw[fill=black] (6, 2) to[diode, l=\(D_1\), -*] (6, 4);
\draw (8, 0) to[R, l=\(R_3\), *-] (8, 2);
\draw[fill=black] (8, 4) to[diode, l=\(D_2\), *-] (8, 2);
\node[op amp, xscale=-1, yscale=-1] (opamp) at (14, 2) {};
\draw ($(opamp.out) + (-1, 0)$) to[short, *-] (opamp.out);
\draw ($(opamp.out) + (-1, 0)$) -- ($(opamp.out) + (-1, 1.5)$);
\draw ($(opamp.out) + (-1, 0)$) -- ($(opamp.out) + (-1, -1.5)$);
\coordinate (opamp plus) at (opamp.+);
\coordinate (opamp minus) at (opamp.-); % - sign in opamp.- causes errors with the |- notation
\draw (opamp plus) -- (opamp plus|-(0, 3.5));
\draw ($(opamp.out) + (-1, 1.5)$) to[R, n=R4, -*] (opamp plus|-(0, 3.5));
\node[below] at (R4.s) {\(R_4\)}; % want name to appear below below
\draw (opamp minus) -- (opamp minus|-(0, 0.5));
\draw ($(opamp.out) + (-1, -1.5)$) to[R, l=\(R_5\), -*] (opamp minus|-(0, 0.5));
\draw (0, 4) -- (2, 4);
\draw (4, 4) -- (opamp plus|-(0, 4));
\draw (15.2, 4) -- (opamp plus);
\draw (0, 0) -- (8, 0);
\draw (8, 0) to[R, l=\(R_6\)] (opamp minus|-(0, 0));
\draw (15.2, 0) -- (opamp minus);
\node[ground] at (8, 0);
\end{tikzpicture}
\end{document}