答案1
\documentclass[border=3.141592]{standalone}
\usepackage{tikz}
\usetikzlibrary{arrows.meta,
decorations.pathreplacing,
calligraphy} % had to be loaded after decorations.pathreplacing
\begin{document}
\begin{tikzpicture}[
> = Straight Barb,
node distance = 8mm and 24mm,
BC/.style = {% Brace Calligraphic
decorate,
decoration={calligraphic brace, #1,% for mirror
pre =moveto, pre length=1pt,
post=moveto, post length=1pt,
raise=6pt, amplitude=6pt},
very thick, thick, pen colour={black}
},
BC/.default = \empty,
dot/.style = {circle, fill, inner sep=2pt, outer sep=0pt},
every label/.append style = {align=center}
]
\draw[->] (0,0.0) node[left=1mm] {$q'(t)$:} --
(8,0.0) node[below left] {$t$};
\draw (4,0.1) -- ++ (0,-0.2) node[below] {$-\frac{1}{b}$};
%
\draw[BC] (0,0) -- node[above=11pt] {$-$} (4,0);
\draw[BC] (4,0) -- node[above=11pt] {$+$} (8,0);
\end{tikzpicture}
\end{document}
答案2
\documentclass{article}
\usepackage{amsmath}
\begin{document}
\begin{equation*}
q'(t)\colon
\makebox[0pt][l]{$
\overbrace{\makebox[2.5cm]{\mathstrut}}^{-}
\!
\makebox[0pt][c]{$\mathop{\vert}\limits_{-\frac{1}{b}}$}
\!
\overbrace{\makebox[2.5cm]{\mathstrut}}^{+}
$}
\makebox[5cm]{\rightarrowfill}_t
\end{equation*}
\end{document}
答案3
\documentclass[border=1cm]{standalone}
\usepackage{tikz}
\usetikzlibrary{decorations.pathreplacing}
\begin{document}
\begin{tikzpicture}
\draw[->](0,0) -- (5,0) node[midway,yshift=-0.75cm](a) {$-\frac{1}{b}$};
\draw (2.5,-0.25) -- (2.5,0.25);
\node[yshift=-0.75cm] at (5,0) {t};
\node[xshift=-0.75cm] at (0,0) {q´t:};
%brace -
\draw [decorate,decoration={brace,amplitude=10pt},xshift=0pt,yshift=10pt]
(0,0) -- (2.5,0) node [black,midway,xshift=0cm,yshift=0.5cm]
{\footnotesize -};
%brace +
\draw [decorate,decoration={brace,amplitude=10pt},xshift=0pt,yshift=10pt]
(2.5,0) -- (5,0) node [black,midway,xshift=0cm,yshift=0.5cm]
{\footnotesize +};
\end{tikzpicture}
\end{document}