更新 1：

Question

我正在为学生编写一本包含家庭作业练习及其解决方案的练习册。对于“家庭作业练习”，homework-exercise-solution我使用 定义了自定义环境amsthm。

最终，我正在寻找解决方法这是我的另一个问题我自己通过将“家庭作业练习”包装homework-exercise-solution到包中的 colorbox 环境中，tcolorbox使用选项invisible通过自定义包开关显示空幻影框。（一旦我把一切都做得更完美了，我就会回答我自己的问题。）

现在，这意味着家庭作业练习和解决方案分散在整个练习册中，这是没问题的，因为它们放在相关内容的旁边。

不过，我想此外在文档末尾打印包含所有homework-exercise和环境的副本的页面，以确保学生对必须完成的任务有一个很好的简短概述（并且我的导师有一个很好的简短的方法来检查填写的解决方案表）。homework-exercise-solution

我如何才能生成某些类型的所有环境的副本，同时保留它们第一次出现时分配的编号？（但是，必须调整重复项的标签，以免重写对最初放置的环境的引用）

附件是 MWE 及其生成的输出的屏幕截图

% 
% 
% 
\documentclass{article}

\begin{filecontents*}{testpackage.sty}
    \NeedsTeXFormat{LaTeX2e}
    \ProvidesPackage{mw88-script}[2021/08/25 LaTeX package for toggling solutions]
    
    \RequirePackage{tcolorbox}
    
    \newcommand{\visibility}{invisible}
    
    \DeclareOption{showsolutions}{\renewcommand{\visibility}{visible}}
    \DeclareOption*{\PackageWarning{examplepackage}{Unknown ‘\CurrentOption’}}
    \ProcessOptions\relax
    
    
    \tcolorboxenvironment{exercise-homework}{
    }
    \tcolorboxenvironment{exercise-homework-solution}{
    \visibility
    }
    \end{filecontents*}

\usepackage{mwe}
\usepackage{amssymb, amsmath, amsthm, mathtools}
% \usepackage{testpackage}
\usepackage[showsolutions]{testpackage}



\theoremstyle{plain}{
\newtheorem{exercise-homework}{Hausaufgabe}
}

\theoremstyle{plain}{
\newtheorem{exercise-homework-solution}{Lösung}
}
% 
% 
% 
\begin{document}
\section{This is the guided workflow}
    Here are explanatory things and prerequisites necessary to solve the exercise.
    \begin{exercise-homework}
        Show that $(\mathbb{R}, +, \cdot)$ is a field.
    \end{exercise-homework}

    \begin{exercise-homework-solution}%
        Let $a, b, c \in \mathbb{R}$ arbitrary. Then, we show the following properties:
        \begin{description}
            \item[Commutativity of addition]  $a + b = b+ a$.
            \item[Associativity of addition] $a +(b + c) = (a+b) +c$.
            \item[Additive identity] $0 \in \mathbb{R}$, and $a +0 = a $.
            \item[Additive inverse] for each $a \in \mathbb{R}$, there exists $-a \in \mathbb{R}$, sch that $a + (-a) = 0$.
            \item[Commutativity of multiplication] $a \cdot b = b \cdot a$.
            \item[Associativity of multiplications] $a \cdot (b \dot c) = (a \cdot b) \cdot c$.
            \item[Multiplicative identity] $1 \in \mathbb{R}$, such that $1 \cdot a = a$.
            \item[Multiplicative inverse] for each $a \in \mathbb{R}$, there exists $a^{-1}\in \mathbb{R}$, such that $a \cdot a^{-1} = 1$.      
            \item[Distributivity] $a\cdot (b + c) = (a \cdot b) + (a \cdot c)$. 
        \end{description}
        These are the necessary and sufficient properties of a field, hence $(\mathbb{R}, +, \cdot)$ is a field.
    \end{exercise-homework-solution}

    From here, the workbook content continues. There are going to be more exercises and solutions.

    \section*{Appendix}
        Here I want duplicates of the exercise and solutions from above.
\end{document}

可以在包选项中切换解决方案内容的显示。

更新 1：

进一步的调查显示，我应该能够使用thm-restate来自的包来thmtools重述定理类环境。但是，开箱即thm-restate用效果不佳。请参阅下面的 MWE 和附加的屏幕截图：重述的环境未包装在 tcolorbox 中。tcolorbox

\documentclass[a4paper]{article}

\usepackage{thmtools}
\usepackage{thm-restate}
\usepackage[dvipsnames]{xcolor}
\usepackage[many]{tcolorbox}





\declaretheorem[name=Exercise, style=remark]{exercise}
\tcolorboxenvironment{exercise}{colframe=red!75!black}

\begin{document}

\noindent We start using the {\ttfamily exercise}-environment:
\begin{exercise}[restate=restatekey]
  This is a demonstrational exercise.
\end{exercise}

\noindent and try to restate this:
\restatekey*

\noindent then follow it up with a {\ttfamily restatable}-environment
\begin{restatable}{exercise}{extest}\label{ex:test}
  This is a restatable exercise.
\end{restatable}


\noindent In the following, there's the restated {\ttfamily restatable}-exercise:
\extest*

\end{document}

Answer 1

分步解决

解决缺失的tcolorbox环境restatable：

感谢这个仅稍微相关的问题，我能够让重述的环境与原始事件restatable共享密钥：tcolorbox

\documentclass[a4paper]{article}

\usepackage{thmtools}
\usepackage{thm-restate}
\usepackage[dvipsnames]{xcolor}
\usepackage[many]{tcolorbox}

\makeatletter
\define@key{thmdef}{tcolorbox}[{}]{%
\thmt@trytwice{}{%
\RequirePackage{tcolorbox}%
\RequirePackage{thm-patch}%
\addtotheorempreheadhook[\thmt@envname]{%
\begin{tcolorbox}[#1]}%
\addtotheorempostfoothook[\thmt@envname]{\end{tcolorbox}}%
}%
}
\makeatother


\declaretheorem[name=Exercise,
style=remark,
tcolorbox={
    colframe={red!75!black},
    }]{exercise}


\begin{document}


\noindent A {\ttfamily restatable}-environment
\begin{restatable}{exercise}{extest}\label{ex:test}
This is a restatable exercise.
\end{restatable}


\noindent In the following, there's the restated {\ttfamily restatable}-exercise:
\extest*



\end{document}

输出如下所示：

但是，您不能使用以下形式来插入可重置环境：

\begin{exercise}[restate=restatekey]
    This is a demonstrational exercise.
\end{exercise}

\restatekey*

将所有内容整合成最终的解决方案

我希望这对其他人有所帮助。我的大量注释的 MWE 代码

\begin{filecontents*}[overwrite]{testpackage.sty}
  \NeedsTeXFormat{LaTeX2e}
  \ProvidesPackage{testpackage}[2021/08/25 LaTeX package for toggling solutions]

  \RequirePackage{tcolorbox}
  \RequirePackage{ifthen}
  \RequirePackage{comment}
  \RequirePackage{environ}
  \RequirePackage{verbatim}


  % process the options regarding solution visibility
  \newcommand{\visibility}{visible}
  \DeclareOption{hidesolutions}{\renewcommand{\visibility}{hidden}}
  \DeclareOption{nosolutions}{\renewcommand{\visibility}{empty}}

  %  process all unknown options
  \DeclareOption*{\PackageWarning{testpackage}{Unknown ‘\CurrentOption’}}
  \ProcessOptions\relax


  % this is the colorbox fix from first part of the solution
  \define@key{thmdef}{tcolorbox}[]{%
    \thmt@trytwice{}{%
      \RequirePackage{tcolorbox}%
      \RequirePackage{thm-patch}%
      \addtotheorempreheadhook[\thmt@envname]{%
      \begin{tcolorbox}[#1]}%
      \addtotheorempostfoothook[\thmt@envname]{\end{tcolorbox}}%
      }%
    }

  %  define a list for storing the exercises
\def\exercises@list{}
%  define a list for storing the exercises with their solutions
\def\exercisesandsolutions@list{}
%  define a list for storing the exercises with their solutions set invivible
\def\exercisesandsolutionsinvisible@list{}
%  define a list to store only the solutions
\def\solutions@list{}

\newcounter{exercise@cnt}
\newcounter{solution@cnt}
%  define the exercise theorem environment (for inner use)
\declaretheorem[name={Exercise},numberwithin=section, tcolorbox={
  colframe={red!75!black},
  }]{thmexercise}
%  define the solution theorem environment (for inner use)
\declaretheorem[name={Solution},numberwithin=section, tcolorbox={
  colframe={black},
  }]{thmsolution}
  %  define the invisible solution theorem environment (for inner use)
\declaretheorem[name={Solution},numberwithin=section, tcolorbox={
  colframe={black},
  invisible
  }]{thmsolutionhidden}


%  define the actual exercise environment
\newenvironment{exercise}[1][]{%
  \stepcounter{exercise@cnt}%
  % fully expand the counter representation
  % before calling \restatable
  \begingroup\edef\x{\endgroup
    \noexpand\restatable[{#1}]{thmexercise}{exercise-\Alph{exercise@cnt}}%
  }\x
}{\endrestatable
  \xappto\exercises@list{%
    \expandafter\noexpand\csname exercise-\Alph{exercise@cnt}\endcsname*%
  }%
  % append the exercise also to all other relevant lists
  \xappto\exercisesandsolutions@list{%
    \expandafter\noexpand\csname exercise-\Alph{exercise@cnt}\endcsname*%
  }%
  \xappto\exercisesandsolutionsinvisible@list{%
    \expandafter\noexpand\csname exercise-\Alph{exercise@cnt}\endcsname*%
  }%
}

%  define the actual solution environment
\newenvironment{solution}[1][]{%
  \stepcounter{solution@cnt}%
  % fully expand the counter representation
  % before calling \restatable
  \def\x{}
  \ifthenelse{\equal{\visibility}{visible}}{
      \begingroup\edef\x{\endgroup
        \noexpand\restatable[{#1}]{thmsolution}{solution-\Alph{solution@cnt}}%
      }}{}

  \ifthenelse{\equal{\visibility}{hidden}}{
      \begingroup\edef\x{\endgroup
        \noexpand\restatable[{#1}]{thmsolutionhidden}{solution-\Alph{solution@cnt}}%
      }}{}

  \ifthenelse{\equal{\visibility}{empty}}{
    \setbox0\vbox\bgroup
  }{
    \x%
  }
}{
  \ifthenelse{{\equal{\visibility}{visible}}\OR{\equal{\visibility}{hidden}}}{
    \endrestatable
      \xappto\solutions@list{%
        \expandafter\noexpand\csname solution-\Alph{solution@cnt}\endcsname*%
      }%
      % append the exercise also to all other relevant lists
      \xappto\exercisesandsolutions@list{%
        \expandafter\noexpand\csname solution-\Alph{solution@cnt}\endcsname*%
      }%
    }{
      \egroup
    }
}



% define shortcuts for displaying the lists
\newcommand{\allexercises}{\exercises@list}
\newcommand{\allsolutions}{\solutions@list}
\newcommand{\allexercisesandsolutions}{\exercisesandsolutions@list}

\end{filecontents*}

\documentclass{article}




\usepackage[a4paper, margin=1in]{geometry}

\usepackage{thmtools}
\usepackage{thm-restate}
\usepackage[dvipsnames]{xcolor}
\usepackage[many]{tcolorbox}

\usepackage[]{testpackage}
% \usepackage[hidesolutions]{testpackage}
% \usepackage[nosolutions]{testpackage}







\begin{document}



\section{Originals}

Some text.

\begin{exercise}[Title?]
  This is the first recommendation.
\end{exercise}

We can of course have text between solution and exercise.

\begin{solution}[A named solution]
  This is the solution after the first exercise.
\end{solution}

Some text.

\begin{exercise}
  This is the second recommendation.
\end{exercise}

And even more text.

\begin{solution}
  This is the solution after the second exercise.
\end{solution}

Some text.

\section{All Exercises}
\allexercises
\section{All Solutions}
\allsolutions
\section{All Exercises with Solutions}
\allexercisesandsolutions




\end{document}

产生以下输出（基于包选项）：

我现在可以使用testpackage选项| hidesolutions | emptysolutions来产生不同的预期结果。