我使用了@Qrrbrbirlbel 提出的技术
使我的求和符号足够大。
\documentclass[11pt,oneside,openany]{book}
\usepackage[a4paper, left=1.5cm, right=1.5cm, top=3cm, bottom=3cm]{geometry}
\usepackage{array}
\usepackage[table]{xcolor}
\usepackage{amsmath}
\usepackage{amssymb}
\usepackage{amsthm}
\usepackage{graphicx}
\usepackage{calc}
\usepackage{actuarialsymbol}
%I copied this part from tex.stackexchange.com written by @Qrrbrbirlbel
\newlength{\depthofsumsign}
\setlength{\depthofsumsign}{\depthof{$\sum$}}
\newlength{\totalheightofsumsign}
\newlength{\heightanddepthofargument}
\newcommand{\nsum}[1][1.4]{% only for \displaystyle
\mathop{%
\raisebox
{-#1\depthofsumsign+1\depthofsumsign}
{\scalebox
{#1}
{$\displaystyle\sum$}%
}
}
}
\newcommand{\resum}[1]{%
\def\s{#1}
\mathop{
\mathpalette\resumaux{#1}
}
}
\newcommand{\resumaux}[2]{% internally
\sbox0{$#1#2$}
\sbox1{$#1\sum$}
\setlength{\heightanddepthofargument}{\wd0+\dp0}
\setlength{\totalheightofsumsign}{\wd1+\dp1}
\def\quot{\DivideLengths{\heightanddepthofargument}{\totalheightofsumsign}}
\nsum[\quot]%
}
% http://tex.stackexchange.com/a/6424/16595
\makeatletter
\newcommand*{\DivideLengths}[2]{%
\strip@pt\dimexpr\number\numexpr\number\dimexpr#1\relax*65536/\number\dimexpr#2\relax\relax sp\relax
}
\makeatother
\begin{document}
\begin{align}
CHN &=\nsum[1.7]\limits_{\forall x}\actsymb[x]{f}{b}[T]\cdot\dfrac{\lx{b}[B]}{
\lx{0}[F]}\nsum[2.5]\limits_{s=0}\dfrac{\actsymb[n]{f}{r}[E]\cdot\dfrac{\lx{q}[W]
}{\lx{6}[Y]}}{\actsymb[m]{f}{q}[B]}
\end{align}
\end{document}
我不知道该如何调整。我在此恳请大家帮助。
答案1
虽然可以做到,但是看起来很糟糕!
您还可以使用 pgfmath 来计算比例因子。
\documentclass[11pt,oneside,openany]{book}
\usepackage[a4paper, left=1.5cm, right=1.5cm, top=3cm, bottom=3cm]{geometry}
\usepackage{array}
\usepackage[table]{xcolor}
\usepackage{amsmath}
\usepackage{amssymb}
\usepackage{amsthm}
\usepackage{graphicx}
\usepackage{calc}
\usepackage{actuarialsymbol}
%I copied this part from tex.stackexchange.com written by @Qrrbrbirlbel
\newlength{\depthofsumsign}
\setlength{\depthofsumsign}{\depthof{$\sum$}}
\newlength{\totalheightofsumsign}
\newlength{\heightanddepthofargument}
\newsavebox{\tempbox}
\newcommand{\nsum}[1][1.4]{% only for \displaystyle
\mathop{%
\raisebox
{-#1\depthofsumsign+1\depthofsumsign}
{\scalebox
{#1}
{$\displaystyle\sum$}%
}
}
}
\newcommand{\resum}[1]{%
\def\s{#1}
\mathop{
\mathpalette\resumaux{#1}
}
}
\newcommand{\resumaux}[2]{% internally
\sbox0{$#1#2$}
\sbox1{$#1\sum$}
\setlength{\heightanddepthofargument}{\wd0+\dp0}
\setlength{\totalheightofsumsign}{\wd1+\dp1}
\def\quot{\DivideLengths{\heightanddepthofargument}{\totalheightofsumsign}}
\nsum[\quot]%
}
% http://tex.stackexchange.com/a/6424/16595
\makeatletter
\newcommand*{\DivideLengths}[2]{%
\strip@pt\dimexpr\number\numexpr\number\dimexpr#1\relax*65536/\number\dimexpr#2\relax\relax sp\relax
}
\makeatother
\begin{document}
\savebox{\tempbox}{$\dfrac{\actsymb[n]{f}{r}[E]\cdot\dfrac{\lx{q}[W]}{\lx{6}[Y]}}{\actsymb[m]{f}{q}[B]}$}% measure height
\begin{align}
CHN &=\nsum[1.7]\limits_{\forall x}\actsymb[x]{f}{b}[T]\cdot\dfrac{\lx{b}[B]}{
\lx{0}[F]}\resizebox{!}{\ht\tempbox}{$\sum\limits_{s=0}$} \usebox\tempbox
\end{align}
\end{document}