我正在尝试找到一个代码，让学生选择正确的答案。我知道如何做多项选择题。但是，我希望这道题能全部放在一个问题中，而不是分散开来。有什么建议吗？
目前我已经为学生创建了一个空间来写下他们的答案。但是，我更希望提供两个选项供他们选择。
因此，我尝试添加格式化的“还原/氧化”
在每个化学半方程式/方程式的末尾。
\documentclass[
a4paper,
12pt,
addpoints,
noanswers
]
{exam}
\usepackage[version=4]{mhchem}
\newcommand{\subject}{Chemistry}
\newcommand{\paper}{SAT 2: Topic 3}
\newcommand{\papershort}{SAT 2}
\newcommand{\conditions}{90 Minutes, Exam Conditions}
\newcommand{\duedate}{June 26}
\begin{document}
\begin{questions}
\ifprintanswers
\else
\fullwidth{You and your supervisor must \textbf{write your names}
to agree that exam conditions were satisfied.}
\fi
\question
Identify these reactions as either oxidation or reduction (circle answer):
\begin{parts}
\part[1]
\ce{Ca -> Ca^2+ + 2e-}
\begin{solutionordottedlines}[.25in]
oxidation
\end{solutionordottedlines}
\part[1]
\ce{F2 +2e- -> 2F-}
\begin{solutionordottedlines}[.25in]
reduction
\end{solutionordottedlines}
\part[1]
\ce{H2O2 + 2H+ +2e- -> 2H2O}
\begin{solutionordottedlines}[.25in]
reduction
\end{solutionordottedlines}
\part[1]
\ce{Cu -> Cu^2+ + 2e-}
\begin{solutionordottedlines}[.25in]
oxidation
\end{solutionordottedlines}
\end{parts}
\end{questions}
\end{document}
答案1
我是否正确，你只是想获得：
如果是这样，那么您只需 Reduction /Oxidation在每个问题末尾添加即可实现此目的。或者，您可以使用类似
\newcommand\ReductionOxidation{\hfill Reduction / Oxidation}
这样做。\hfill将 推reduction/oxidation到右边距。如果您愿意，您可以更“花哨”地定义
\newcommand\ReductionOxidation[1]{\ce{#1}\hfill Reduction / Oxidation}
然后写下\ReductionOxidation{Ca -> Ca^2+ + 2e-}问题——这样你就不用再输入了\ce。以下是上述输出的完整 MWE：
\documentclass[ a4paper, 12pt, addpoints, noanswers ] {exam}
\usepackage[version=4]{mhchem}
\newcommand{\subject}{Chemistry}
\newcommand{\paper}{SAT 2: Topic 3}
\newcommand{\papershort}{SAT 2}
\newcommand{\conditions}{90 Minutes, Exam Conditions}
\newcommand{\duedate}{June 26}
\newcommand\ReductionOxidation{\hfill Reduction / Oxidation}
\begin{document}
\begin{questions}
\ifprintanswers
\else
\fullwidth{You and your supervisor must \textbf{write your names} to agree that exam conditions were satisfied.}
\fi
\question
Identify these reactions as either oxidation or reduction (circle answer):
\begin{parts}
\part[1]
\ce{Ca -> Ca^2+ + 2e-}\ReductionOxidation
\begin{solutionordottedlines}[.25in]
oxidation
\end{solutionordottedlines}
\part[1]
\ce{F2 +2e- -> 2F-}\ReductionOxidation
\begin{solutionordottedlines}[.25in]
reduction
\end{solutionordottedlines}
\part[1]
\ce{H2O2 + 2H+ +2e- -> 2H2O}\ReductionOxidation
\begin{solutionordottedlines}[.25in]
reduction
\end{solutionordottedlines}
\part[1]
\ce{Cu -> Cu^2+ + 2e-}\ReductionOxidation
\begin{solutionordottedlines}[.25in]
oxidation
\end{solutionordottedlines}
\end{parts}
\end{questions}
\end{document}
编辑
您可能还会更加好奇，将的定义替换\ReductionOxidation为：
\usepackage{tikz}
\usetikzlibrary{shapes.geometric}
\newcommand\ellipse[1]{\tikz[baseline=(current bounding box.center)]{\node[ellipse,draw]{#1};}}
\newcommand\ReductionOxidation{\hfill\ellipse{Reduction}\space\ellipse{Oxidation}}
生产：
