使用 Tikz Fit 绘制覆盖 Tikz 链的节点

Question

使用 绘制节点链tikz chains。我想绘制一个覆盖链节点的矩形节点（或者，多个覆盖子集的矩形节点）。我正在使用tikz fit。

不幸的是，按照我的使用方式，矩形节点被视为链的一部分。因此，绘制到矩形位置的附加连接边有点混乱。以下是 MWE：

\documentclass[border=5pt]{standalone}

\usepackage{tikz}
\usetikzlibrary{chains, fit}

\begin{document}
\begin{tikzpicture}[start chain, node distance=5mm, every node/.style={draw, on chain, join}, every join/.style=->]
  \node (a)  {a};
  \node (b)  {b};
  \node  (c)  {c};
  \node  (d)  {d};
  \begin{scope} [start branch=numbers, every join/.style=<-]
    \node (1) [on chain=going above] {1};
    \node (2) [on chain=going above] {2};
  \end{scope}
  \node  (e)  {e};
  \node (fit2) [draw, inner sep=2pt, fit=(a) (b) ] {};
  \node (fit1) [draw, inner sep=2pt, fit=(d) (1) (e)] {};
\end{tikzpicture}
\end{document}

有和没有覆盖矩形的结果分别是

Answer 1

不要将最后两个节点包含在您说every node/.style=on chain或覆盖every node样式的范围内再次。

代码A

\documentclass[border=5pt, tikz]{standalone}
\usetikzlibrary{chains, fit}

\begin{document}
\begin{tikzpicture}[node distance=5mm]
 \begin{scope}[start chain, every node/.style={draw, on chain, join}, every join/.style=->]
  \node (a)  {a};
  \node (b)  {b};
  \node  (c)  {c};
  \node  (d)  {d};
  \begin{scope} [start branch=numbers, every join/.style=<-]
    \node (1) [on chain=going above] {1};
    \node (2) [on chain=going above] {2};
  \end{scope}
  \node  (e)  {e};
 \end{scope}
  \node (fit2) [draw, inner sep=2pt, fit=(a) (b) ] {};
  \node (fit1) [draw, inner sep=2pt, fit=(d) (1) (e)] {};
\end{tikzpicture}
\end{document}

代码 B

\documentclass[border=5pt, tikz]{standalone}
\usetikzlibrary{chains, fit}

\begin{document}
\begin{tikzpicture}[node distance=5mm, start chain, every node/.style={draw, on chain, join}, every join/.style=->]
  \node (a)  {a};
  \node (b)  {b};
  \node  (c)  {c};
  \node  (d)  {d};
  \begin{scope} [start branch=numbers, every join/.style=<-]
    \node (1) [on chain=going above] {1};
    \node (2) [on chain=going above] {2};
  \end{scope}
  \node  (e)  {e};
  \tikzset{every node/.style={draw, inner sep=+2pt}}
  \node (fit2) [fit=(a) (b) ] {};
  \node (fit1) [fit=(d) (1) (e)] {};
\end{tikzpicture}
\end{document}