\documentclass[20pt]{beamer}
\geometry{ papersize = {27cm, 21cm}}
\usepackage[english]{babel}
\usepackage{mathrsfs, booktabs, multirow}
\usepackage{amsmath}
\usetheme{Darmstadt}
\begin{document}
\begin{frame}
\frametitle{Maxwell Equation}\linespread{0.5}
\huge
\begin{equation}
\vec A = \frac{\mu}{4\pi }\int_V {\frac{{\vec J(\vec x')dV'}}{r}}
\end{equation}
\begin{equation}
\nabla \cdot \vec D =\rho
\end{equation}
\end{frame}
\end{document}
我知道这个问题与有关\huge
。拉丁字母和希腊字母的增加比例不同,但如何解决呢?
答案1
现在注释掉的前两行是问题的根源。水平间距已dV'
更正。
%\documentclass[20pt]{beamer}
\documentclass{beamer}
%\geometry{ papersize = {27cm, 21cm}}
\usepackage[english]{babel}
\usepackage{mathrsfs, booktabs, multirow}
\usepackage{amsmath}
\usetheme{Darmstadt}
\begin{document}
\begin{frame}
\frametitle{Maxwell Equation}\linespread{0.5}
\huge
\begin{equation}
%\vec A = \frac{\mu}{4\pi }\int_V {\frac{{\vec J(\vec x')dV'}}{r}}
\vec A = \frac{\mu}{4\pi }\int_V {\frac{{\vec J(\vec x')\,dV'}}{r}}
\end{equation}
\begin{equation}
\nabla \cdot \vec D =\rho
\end{equation}
\end{frame}
\end{document}