我想删除表格中的整行。
一个不太好看的解决方案是使用soul
包并删除每个单元格中的文本。
\documentclass[border=5pt]{article}
\usepackage{multirow}
\usepackage{tabls}
\usepackage{booktabs}
\usepackage{rotating}
\usepackage{soul}
\begin{document}
\begin{sidewaystable}[htbp]
\centering
\begin{tabular}{ lcc|cc|cc|cc|cc }
\cmidrule{2-11} & \multicolumn{2}{c}{\textbf{1 week}} & \multicolumn{2}{c}{\textbf{2 weeks}} & \multicolumn{2}{c}{\textbf{3 weeks}} & \multicolumn{2}{c}{\textbf{4 weeks}} & \multicolumn{2}{c}{\textbf{5 weeks}} \\
\cmidrule{2-11}
\cmidrule{2-11} \multicolumn{1}{l}{} & $<\rho>$ & \#vals. & $<\rho>$ & \#vals. & $<\rho>$ & \#vals. & $<\rho>$ & \#vals. & $<\rho>$ & \#vals. \\
\hline
\st{Bridging Centrality} & \st{0.38} & \st{2} & \st{0.52} & \st{3} & \st{0.48} & \st{6} & \st{0.52} & \st{12} & \st{0.45} & \st{5} \\
\hline
Bridging Centrality & 0.38 & 2 & 0.52 & 3 & 0.48 & 6 & 0.52 & 12 & 0.45 & 5 \\
\hline
\end{tabular}%
\label{tab:addlabel}%
\caption{$<\rho>$ is the mean of the correlation coefficients that have a significant ($<0.05$) p-value. \#vals indicates the number (out of 20) of correlation coefficient that are significant.}
\end{sidewaystable}%
\end{document}
有没有更好的选择?
答案1
这是一种简单的方法,无需soul
:一个简单的\hline
和一个\vspace
。
\documentclass[border=5pt]{article}
\usepackage{multirow}
\usepackage{tabls}
\usepackage{booktabs}
\usepackage{rotating}
\begin{document}
\begin{sidewaystable}[htbp]
\centering
\begin{tabular}{ lcc|cc|cc|cc|cc }
\cmidrule{2-11} & \multicolumn{2}{c}{\textbf{1 week}} & \multicolumn{2}{c}{\textbf{2 weeks}} & \multicolumn{2}{c}{\textbf{3 weeks}} & \multicolumn{2}{c}{\textbf{4 weeks}} & \multicolumn{2}{c}{\textbf{5 weeks}} \\
\cmidrule{2-11}
\cmidrule{2-11} \multicolumn{1}{l}{} & $<\rho>$ & \#vals. & $<\rho>$ & \#vals. & $<\rho>$ & \#vals. & $<\rho>$ & \#vals. & $<\rho>$ & \#vals. \\
\hline
Bridging Centrality & 0.38 & 2 & 0.52 & 3 & 0.48 & 6 & 0.52 & 12 & 0.45 & 5 \\[-2.2ex]
\hline\noalign{\vspace{\dimexpr 2.2ex-\doublerulesep}}
\hline
Bridging Centrality & 0.38 & 2 & 0.52 & 3 & 0.48 & 6 & 0.52 & 12 & 0.45 & 5 \\
\hline
\end{tabular}%
\label{tab:addlabel}%
\caption{$<\rho>$ is the mean of the correlation coefficients that have a significant ($<0.05$) p-value. \#vals indicates the number (out of 20) of correlation coefficient that are significant.}
\end{sidewaystable}%
\end{document}
答案2
{NiceTabular}
在的环境中nicematrix
,您可以轻松地使用 TikZ 和 在数组中创建的节点绘制您想要的任何规则nicematrix
。
\documentclass[border=5pt]{article}
\usepackage{booktabs}
\usepackage{rotating}
\usepackage{nicematrix,tikz}
\begin{document}
\begin{sidewaystable}[htbp]
\centering
\newcolumntype{'}{!{\vrule}}
\begin{NiceTabular}{ lcc'cc'cc'cc'cc }
\cmidrule{2-11} & \multicolumn{2}{c}{\textbf{1 week}} & \multicolumn{2}{c}{\textbf{2 weeks}} & \multicolumn{2}{c}{\textbf{3 weeks}} & \multicolumn{2}{c}{\textbf{4 weeks}} & \multicolumn{2}{c}{\textbf{5 weeks}} \\
\cmidrule{2-11}
\cmidrule{2-11} \multicolumn{1}{l}{} & $\langle\rho\rangle$ & \#vals. & $\langle\rho\rangle$ & \#vals. & $\langle\rho\rangle$ & \#vals. & $\langle\rho\rangle$ & \#vals. & $\langle\rho\rangle$ & \#vals. \\
\hline
Bridging Centrality & 0.38 & 2 & 0.52 & 3 & 0.48 & 6 & 0.52 & 12 & 0.45 & 5 \\
\hline
Bridging Centrality & 0.38 & 2 & 0.52 & 3 & 0.48 & 6 & 0.52 & 12 & 0.45 & 5 \\
\hline
\CodeAfter
\tikz \draw [red,double] (3.5-|1) -- (3.5-|last) ;
\end{NiceTabular}%
\label{tab:addlabel}%
\caption{$\langle\rho\rangle$ is the mean of the correlation coefficients that have a significant ($<0.05$) p-value. \#vals
indicates the number (out of 20) of correlation coefficient that are significant.}
\end{sidewaystable}%
\end{document}