我设计了一个长表格,问题是这个表格显示在文档底部,即使将段落设置为显示在表格之后,它也会显示在表格之前。我也使用 [!ht] 将表格保持在我想要的位置,但似乎对它没有影响。
\documentclass[review]{elsarticle}
\DeclareGraphicsExtensions{.pdf,.gif,.jpg}
\usepackage{lineno}
\modulolinenumbers[5]
\usepackage{graphicx}
\usepackage{amssymb,amsmath,nccmath}
\usepackage{cclicenses}
%%\usepackage{caption} % is loaded automatically by 'subcaption'
\usepackage{lscape,array}
\newcolumntype{C}[1]{>{\centering\arraybackslash}p{#1}} % centered 'p' col.
%%\usepackage{natbib} % is loaded automatically by elsarticle doc class
\usepackage{subcaption}
\usepackage{framed} % Framing content
\usepackage{nomencl} % Nomenclature package
\makenomenclature
\setlength{\nomitemsep}{-\parskip}\usepackage{booktabs,multirow}
%% Load the next two packages *last*:
\usepackage[colorlinks]{hyperref}
\usepackage[nameinlink]{cleveref}
\journal{Journal of \LaTeX\ Templates}
\bibliographystyle{elsarticle-num}
\begin{document}
\section{Introduction}
blablablablablablablablablablablablablabllabl\\blablablablabl\\
\begin{table}[!h]
\centering
\begin{tabular}{@{} c *{3}{C{0.45cm}} *{2}{C{1.69cm}} c c @{}}
\toprule
Voltage N\textsuperscript{o} & \multicolumn{3}{c}{Switching states} &
\multicolumn{2}{c}{Voltage output} & Magnitude & Phase \\
\cmidrule(lr){2-4} \cmidrule(lr){5-6}
$V_n$ & $S_a$ & $S_b$ & $S_c$ & $V_{\alpha}$ & $V_{\beta}$ &
$U_{\mathrm{ref}}$ & $\alpha$ \\
\midrule
$V_{0o}$ & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\
$V_{0p}$ & 1 & 1 & 1 & 0 & 0 & 0 & 0 \\
$V_{0n}$ & -1 & -1 & -1 & 0 & 0 & 0 & 0 \\
$V_{1p}$ & 1 & 0 & 0 & $U_{dc}/3$ & 0 & $U_{dc}/3$
& 0 \\
$V_{1n}$ & 0 & -1 & -1 & $U_{dc}/3$ & 0 & $U_{dc}/3$ & 0
\\
$V_{2p}$ & 1 & 1 & 0 & $U_{dc}/6$ & $\sqrt{3}\,U_{dc}/6$ & $U_{dc}/3$
& $\pi/3$ \\
$V_{2n}$ & 0 & 0 & -1 & $U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & $\pi/3$ \\
$V_{3p}$ & 0 & 1 & 0 & -$U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 2$\pi/3$ \\
$V_{3n}$ & -1 & 0 & -1 & -$U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 2$\pi/3$ \\
$V_{4p}$ & 0 & 1 & 1 & -$U_{dc}$/3 & 0 & $U_{dc}$/3 & $\pi$ \\
$V_{4n}$ & -1 & 0 & 0 & -$U_{dc}$/3 & 0 & $U_{dc}$/3 & $\pi$ \\
$V_{5p}$ & 0 & 0 & 1 & -$U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 4$\pi$/3 \\
$V_{5n}$ & -1 & -1 & 0 & -$U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 4$\pi$/3 \\
$V_{6p}$ & 1 & 0 & 1 & $U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 5$\pi$/3 \\
$V_{6n}$ & 0 & -1 & 0 & $U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 5$\pi$/3 \\
$V_{7}$ & 1 & 0 & -1 & $U_{dc}$/2 & $\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & $\pi$/6 \\
$V_{8}$ & 0 & 1 & -1 & 0 & $\sqrt{3}$ $U_{dc}/3$ & $\sqrt{3}$
$U_{dc}$/3 & $\pi$/2 \\
$V_{9}$ & -1 & 1 & 0 & -$U_{dc}$/2 & $\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 5$\pi$/6 \\
$V_{10}$ & -1 & 0 & 1 & -$U_{dc}$/2 & -$\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 7$\pi$/6 \\
$V_{11}$ & 0 & -1 & 1 & 0 & -$\sqrt{3}$ $U_{dc}/3$ & $\sqrt{3}$
$U_{dc}$/3 & 3$\pi$/2 \\
$V_{12}$ & 1 & -1 & 0 & $U_{dc}$/2 & -$\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 11$\pi$/6 \\
$V_{13}$ & 1 & -1 & -1 & 2$U_{dc}$/3 & 0 & 2 $U_{dc}$/3 & 0 \\
$V_{14}$ & 1 & 1 & -1 & $U_{dc}$/3 & $\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & $\pi$/3 \\
$V_{15}$ & -1 & 1 & -1 & -$U_{dc}$/3 & $\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 2$\pi$/3 \\
$V_{16}$ & -1 & 1 & 1 & -2$U_{dc}$/3 & 0 & 2$U_{dc}$/3 & $\pi$ \\
$V_{17}$ & -1 & -1 & 1 & -$U_{dc}$/3 & -$\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 4$\pi$/3 \\
$V_{18}$ & 1 & -1 & 1 & $U_{dc}$/3 & -$\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 5$\pi$/3 \\
\bottomrule
\end{tabular}
\end{table}
trtrtrtrtrtrtrtrtrtrttaatatatatatatatatat \\
\end{document}
答案1
好了,您的表格填满了整个页面!
为了向您展示这一点,我添加了一个包showframe
,它可视化了文档的最终打字区域和边距。使用这个包,blindtext
我向您的代码添加了一些虚拟文本。
使用以下 MWE
\documentclass[review]{elsarticle}
\DeclareGraphicsExtensions{.pdf,.gif,.jpg}
\usepackage{lineno}
\modulolinenumbers[5]
\usepackage{graphicx}
\usepackage{showframe,blindtext}
\usepackage{amssymb,amsmath,nccmath}
\usepackage{cclicenses}
%%\usepackage{caption} % is loaded automatically by 'subcaption'
\usepackage{lscape,array}
\newcolumntype{C}[1]{>{\centering\arraybackslash}p{#1}} % centered 'p' col.
%%\usepackage{natbib} % is loaded automatically by elsarticle doc class
\usepackage{subcaption}
\usepackage{framed} % Framing content
\usepackage{nomencl} % Nomenclature package
\makenomenclature
\setlength{\nomitemsep}{-\parskip}\usepackage{booktabs,multirow}
%% Load the next two packages *last*:
\usepackage[colorlinks]{hyperref}
\usepackage[nameinlink]{cleveref}
\journal{Journal of \LaTeX\ Templates}
\bibliographystyle{elsarticle-num}
\begin{document}
\section{Introduction}
blablablablablablablablablablablablablabllabl\\blablablablabl\\
\begin{table}[!h]
\centering
\begin{tabular}{@{} c *{3}{C{0.45cm}} *{2}{C{1.69cm}} c c @{}}
\toprule
Voltage N\textsuperscript{o} & \multicolumn{3}{c}{Switching states} &
\multicolumn{2}{c}{Voltage output} & Magnitude & Phase \\
\cmidrule(lr){2-4} \cmidrule(lr){5-6}
$V_n$ & $S_a$ & $S_b$ & $S_c$ & $V_{\alpha}$ & $V_{\beta}$ &
$U_{\mathrm{ref}}$ & $\alpha$ \\
\midrule
$V_{0o}$ & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\
$V_{0p}$ & 1 & 1 & 1 & 0 & 0 & 0 & 0 \\
$V_{0n}$ & -1 & -1 & -1 & 0 & 0 & 0 & 0 \\
$V_{1p}$ & 1 & 0 & 0 & $U_{dc}/3$ & 0 & $U_{dc}/3$
& 0 \\
$V_{1n}$ & 0 & -1 & -1 & $U_{dc}/3$ & 0 & $U_{dc}/3$ & 0
\\
$V_{2p}$ & 1 & 1 & 0 & $U_{dc}/6$ & $\sqrt{3}\,U_{dc}/6$ & $U_{dc}/3$
& $\pi/3$ \\
$V_{2n}$ & 0 & 0 & -1 & $U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & $\pi/3$ \\
$V_{3p}$ & 0 & 1 & 0 & -$U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 2$\pi/3$ \\
$V_{3n}$ & -1 & 0 & -1 & -$U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 2$\pi/3$ \\
$V_{4p}$ & 0 & 1 & 1 & -$U_{dc}$/3 & 0 & $U_{dc}$/3 & $\pi$ \\
$V_{4n}$ & -1 & 0 & 0 & -$U_{dc}$/3 & 0 & $U_{dc}$/3 & $\pi$ \\
$V_{5p}$ & 0 & 0 & 1 & -$U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 4$\pi$/3 \\
$V_{5n}$ & -1 & -1 & 0 & -$U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 4$\pi$/3 \\
$V_{6p}$ & 1 & 0 & 1 & $U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 5$\pi$/3 \\
$V_{6n}$ & 0 & -1 & 0 & $U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 5$\pi$/3 \\
$V_{7}$ & 1 & 0 & -1 & $U_{dc}$/2 & $\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & $\pi$/6 \\
$V_{8}$ & 0 & 1 & -1 & 0 & $\sqrt{3}$ $U_{dc}/3$ & $\sqrt{3}$
$U_{dc}$/3 & $\pi$/2 \\
$V_{9}$ & -1 & 1 & 0 & -$U_{dc}$/2 & $\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 5$\pi$/6 \\
$V_{10}$ & -1 & 0 & 1 & -$U_{dc}$/2 & -$\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 7$\pi$/6 \\
$V_{11}$ & 0 & -1 & 1 & 0 & -$\sqrt{3}$ $U_{dc}/3$ & $\sqrt{3}$
$U_{dc}$/3 & 3$\pi$/2 \\
$V_{12}$ & 1 & -1 & 0 & $U_{dc}$/2 & -$\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 11$\pi$/6 \\
$V_{13}$ & 1 & -1 & -1 & 2$U_{dc}$/3 & 0 & 2 $U_{dc}$/3 & 0 \\
$V_{14}$ & 1 & 1 & -1 & $U_{dc}$/3 & $\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & $\pi$/3 \\
$V_{15}$ & -1 & 1 & -1 & -$U_{dc}$/3 & $\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 2$\pi$/3 \\
$V_{16}$ & -1 & 1 & 1 & -2$U_{dc}$/3 & 0 & 2$U_{dc}$/3 & $\pi$ \\
$V_{17}$ & -1 & -1 & 1 & -$U_{dc}$/3 & -$\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 4$\pi$/3 \\
$V_{18}$ & 1 & -1 & 1 & $U_{dc}$/3 & -$\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 5$\pi$/3 \\
\bottomrule
\end{tabular}
\end{table}
\Blindtext
\end{document}
您将获得以下带有表格的页面,显示它完全填满了整个页面:
编辑:
使用以下 MWE,您的表格将打印longtable
超过两页:
\documentclass[review]{elsarticle}
\DeclareGraphicsExtensions{.pdf,.gif,.jpg}
\usepackage{lineno}
\modulolinenumbers[5]
\usepackage{graphicx}
\usepackage{showframe,blindtext}
\usepackage{longtable} % <==============================================
\usepackage{amssymb,amsmath,nccmath}
\usepackage{cclicenses}
%%\usepackage{caption} % is loaded automatically by 'subcaption'
\usepackage{lscape,array}
\newcolumntype{C}[1]{>{\centering\arraybackslash}p{#1}} % centered 'p' col.
%%\usepackage{natbib} % is loaded automatically by elsarticle doc class
\usepackage{subcaption}
\usepackage{framed} % Framing contents
\usepackage{nomencl} % Nomenclature package
\makenomenclature
\setlength{\nomitemsep}{-\parskip}\usepackage{booktabs,multirow}
%% Load the next two packages *last*:
\usepackage[colorlinks]{hyperref}
\usepackage[nameinlink]{cleveref}
\journal{Journal of \LaTeX\ Templates}
\bibliographystyle{elsarticle-num}
\begin{document}
\section{Introduction}
blablablablablablablablablablablablablabllabl\\blablablablabl\\
\begin{longtable}{@{} c *{3}{C{0.45cm}} *{2}{C{1.69cm}} c c @{}} % <====================
\toprule
Voltage N\textsuperscript{o} & \multicolumn{3}{c}{Switching states} &
\multicolumn{2}{c}{Voltage output} & Magnitude & Phase \\
\cmidrule(lr){2-4} \cmidrule(lr){5-6}
$V_n$ & $S_a$ & $S_b$ & $S_c$ & $V_{\alpha}$ & $V_{\beta}$ &
$U_{\mathrm{ref}}$ & $\alpha$ \\
\midrule
$V_{0o}$ & 0 & 0 & 0 & 0 & 0 & 0 & 0 \\
$V_{0p}$ & 1 & 1 & 1 & 0 & 0 & 0 & 0 \\
$V_{0n}$ & -1 & -1 & -1 & 0 & 0 & 0 & 0 \\
$V_{1p}$ & 1 & 0 & 0 & $U_{dc}/3$ & 0 & $U_{dc}/3$
& 0 \\
$V_{1n}$ & 0 & -1 & -1 & $U_{dc}/3$ & 0 & $U_{dc}/3$ & 0
\\
$V_{2p}$ & 1 & 1 & 0 & $U_{dc}/6$ & $\sqrt{3}\,U_{dc}/6$ & $U_{dc}/3$
& $\pi/3$ \\
$V_{2n}$ & 0 & 0 & -1 & $U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & $\pi/3$ \\
$V_{3p}$ & 0 & 1 & 0 & -$U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 2$\pi/3$ \\
$V_{3n}$ & -1 & 0 & -1 & -$U_{dc}$/6 & $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 2$\pi/3$ \\
$V_{4p}$ & 0 & 1 & 1 & -$U_{dc}$/3 & 0 & $U_{dc}$/3 & $\pi$ \\
$V_{4n}$ & -1 & 0 & 0 & -$U_{dc}$/3 & 0 & $U_{dc}$/3 & $\pi$ \\
$V_{5p}$ & 0 & 0 & 1 & -$U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 4$\pi$/3 \\
$V_{5n}$ & -1 & -1 & 0 & -$U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 4$\pi$/3 \\
$V_{6p}$ & 1 & 0 & 1 & $U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 5$\pi$/3 \\
$V_{6n}$ & 0 & -1 & 0 & $U_{dc}$/6 & - $\sqrt{3}$ $U_{dc}/6$ &
$U_{dc}$/3 & 5$\pi$/3 \\
$V_{7}$ & 1 & 0 & -1 & $U_{dc}$/2 & $\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & $\pi$/6 \\
$V_{8}$ & 0 & 1 & -1 & 0 & $\sqrt{3}$ $U_{dc}/3$ & $\sqrt{3}$
$U_{dc}$/3 & $\pi$/2 \\
$V_{9}$ & -1 & 1 & 0 & -$U_{dc}$/2 & $\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 5$\pi$/6 \\
$V_{10}$ & -1 & 0 & 1 & -$U_{dc}$/2 & -$\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 7$\pi$/6 \\
$V_{11}$ & 0 & -1 & 1 & 0 & -$\sqrt{3}$ $U_{dc}/3$ & $\sqrt{3}$
$U_{dc}$/3 & 3$\pi$/2 \\
$V_{12}$ & 1 & -1 & 0 & $U_{dc}$/2 & -$\sqrt{3}$ $U_{dc}/6$ &
$\sqrt{3}$ $U_{dc}$/3 & 11$\pi$/6 \\
$V_{13}$ & 1 & -1 & -1 & 2$U_{dc}$/3 & 0 & 2 $U_{dc}$/3 & 0 \\
$V_{14}$ & 1 & 1 & -1 & $U_{dc}$/3 & $\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & $\pi$/3 \\
$V_{15}$ & -1 & 1 & -1 & -$U_{dc}$/3 & $\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 2$\pi$/3 \\
$V_{16}$ & -1 & 1 & 1 & -2$U_{dc}$/3 & 0 & 2$U_{dc}$/3 & $\pi$ \\
$V_{17}$ & -1 & -1 & 1 & -$U_{dc}$/3 & -$\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 4$\pi$/3 \\
$V_{18}$ & 1 & -1 & 1 & $U_{dc}$/3 & -$\sqrt{3}$ $U_{dc}/3$ &
2$U_{dc}$/3 & 5$\pi$/3 \\
\bottomrule
\end{longtable}
\Blindtext
\end{document}
这会给你你想要的东西: