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在乳胶表中的一行中创建新行

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在乳胶表中的一行中创建新行

在此处输入图片描述

上面是我的代码生成的表格。而我需要像下面第二张图那样的表格。我搜索了很多，但找不到任何解决方案。有人能帮忙吗？我的代码是

\documentclass[12pt]{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{relsize}
\usepackage{rotating}
\usepackage{lscape}
\usepackage{changepage}
\usepackage{geometry}
\usepackage{makecell}
\usepackage[utf8]{inputenc}
\geometry{legalpaper, landscape, margin=0.2in}
\begin{document}
    %\begin{adjustwidth}{-8cm}{}
    %\begin{landscape}
    \renewcommand{\arraystretch}{1.5}
    \renewcommand{\tabcolsep}{1mm}
    \begin{table}
    \begin{tabular}{|l|l|l|l|}
        \hline
        \textbf{Event}&\textbf{Destination state}&\textbf{Trans. rate}&\textbf{Condition}\\\hline
1. $PU$ AR. A vacant channel exists in the NCRN.&$(i_{n}+1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f)$&$\lambda_P$&At least one vacant channel exists in the NCRN;$B_n(x)< M-R(x)$\\\hline 
    2. $PU$ AR. No vacant channel exists in the NCRN.$SU_{2N}$  terminates&$(i_{n}+1,j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f)$&$\lambda_P$&$B_n(x)=M– R(x); j_{n2} > 0$\\\hline
                3. $PU$ AR. No vacant channel exists in the NCRN.$SU_{1N}$ performs HO to the RCRN.&$(i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1}+1,j_{r2},f)$&$\lambda_P$&$B_n(x) = M – R(x); j_{n2}=0; j_{n1} > 0: B_r(x) < R(x)$\\\hline
            4. $PU$ AR. An $SU_{1N}$ terminates.&$(i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f)$&$\lambda_P$&$B_n(x) = M – R(x); j_{n2}=j_{r2}=0; j_{n1} > 0; B(x)=M$\\\hline
        5. $SU_{1N}$ AR. A vacant channel exists in the NCRN.&$(i_{n},j_{n1}+1,j_{n2},i_{r},j_{r1},j_{r2},f)$&$\lambda_S$&$B_n(x) < M – R(x); B(x) < M$\\\hline
    6. $SU_{1N}$ AR. No vacant channel exists in the NCRN. $SU_{2N}$ terminates.&$(i_{n},j_{n1}+1,j_{n2}-1,i_{r},j_{r1},j_{r2},f)$&$\lambda_S$&$B_n(x)=M – R(x); j_{n2} > 0$\\\hline
 7. $SU_{2N}$ AR. A vacant channel exists in NCRN&$(i_{n},j_{n1},j_{n2}+1,i_{r},j_{r1},j_{r2},f)$&$\lambda_S$&$B_n(x) < M – R(x)$\\\hline
    8. $SU_{2N}$ AR. No vacant channel exists in NCRN. Vacant channel exists in RCRN.&$(i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}+1,f)$&$\lambda_S$&$B_n(x)=M – R(x); B_r(x) < R(x)$\\\hline
        9. $PU$ DP from the NCRN.&$(i_{n}-1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f)$&$i_n\;\mu_P$&There is at least one $PU$ service in the NCRN; $i_n>0$.\\\hline
            10. $PU$ DP from the RCRN.&$(i_{n},j_{n1},j_{n2},i_{r}-1,j_{r1},j_{r2},f)$&$i_r\;\mu_P$&$Ir > 0$\\\hline
                11. $SU_{1N}$ DP from the NCRN.&$(i_{n},j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f)$&$J_{n1}\;\mu_S$&$j_{n1} > 0$\\\hline
            12. $SU_{1N}$ DP from the RCRN. &$(i_{n},j_{n1},j_{n2},i_{r},j_{r1}-1,j_{r2},f)$&$j_{r1}\;\mu_S$&$Jr > 0$\\\hline
         13. $SU_{2N}$ DP from the NCRN.&$(i_{n},j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f)$&$ j_{n2}\;\mu_S$&$ j_{n2} > 0$\\\hline
     14. $SU_{2N}$ DP from the RCRN.&$(i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}-1,f)$&$j_{r1}\;\mu_S$&$j_{r1} > 0$\\\hline
15. Idle channel failure.&$(i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)$&$(M-B(x))\;\lambda_F$&There is at least one idle channel in the CRN; $B(x) < M$\\\hline
    16. An occupied channel fails. An idle channel exists in the CRN.&$(in,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)$&$(B(x)-f)\;\lambda_F$&$F<B(x)<M$ \\\hline
        17. An occupied channel fails. No idle channels exist in the CRN. An $SU_{1N}$ terminates.  &$(i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f+1)$&$(M-f)\;\lambda_F$&$B(x) = M; j_{n1}>0;j_{n2}=j_{r2}=0$\\\hline
            18. An occupied channel fails. No idle channels exist in the CRN. An $SU_{2N}$ terminates.&$    (i_{n}+1,j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f+1)$&$(M-f)\;\lambda_F$&$B(x)=M; j_{n2} > 0$\\\hline
                 19. An occupied channel fails. No idle channels exist in the CRN. A $PU_{N}$ terminates&$  (i_{n}-1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)$&$
                 (M-f)\;\lambda_F$&$B(x) = M; j_{n1}= j_{n2}=j_{r2}=0; i_{n}>0;$ \\\hline
            20. An occupied channel fails. No idle channels exist in the CRN. An $SU_{1R}$ terminates&$ (i_{n},j_{n1},j_{n2},i_{r},j_{r1}-1,j_{r2},f+1)$&$(M-f)\;\lambda_F$&$B(x)=M; B_n(x) = 0; j_{r2}=0; j_{r1}>0; j_{n1}=0;$\\\hline
        21. An occupied channel fails. No idle channels exist in the CRN. An $SU_{2R}$ terminates&$ (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}-1,f+1)$&$(M-f)\;\lambda_F$&$B(x)=M; B_n(x)=M-R(x); j_{r2} > 0.$ \\\hline
    22. An occupied channel fails. No idle channels exist in the CRN. A $PU_R$ terminates&$ (i_{n},j_{n1},j_{n2},i_{r}-1,j_{r1},j_{r2},f+1)$&$(M-f)\;\lambda_F$&$B(x) = M; B_n(x)=j_{r1}=j_{r2}=j_{n2}=0; i_{r}>0$\\\hline
23. A failed channel is repaired&$  (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f-1)$&$F\;\mu_R$&$f>0$\\\hline                 
    \end{tabular}
\end{table}
\renewcommand{\arraystretch}{1}
\end{document}

在此处输入图片描述

答案1

也许你喜欢：

\documentclass[12pt]{article}
\usepackage{geometry}
\geometry{legalpaper, landscape, margin=0.2in}
\usepackage{amsmath,amssymb}
\usepackage{relsize}
\usepackage{rotating}
\usepackage{lscape}
\usepackage{changepage}
\usepackage{booktabs, makecell, tabularx}
%\usepackage[utf8]{inputenc}
\newcounter{tabrow}
\newcolumntype{N}{>{\stepcounter{tabrow}\textbf{\thetabrow}}r}
\newcolumntype{L}{>{\raggedright\arraybackslash}X}

\begin{document}
    \begin{table}
    \renewcommand{\arraystretch}{1.1}
%    \renewcommand{\tabcolsep}{1mm}
\small
\begin{tabularx}{\linewidth}{N 
                             L 
                    *{2}{>{$}l<{$}}
                         >{$}L<{$}}
\toprule
\multicolumn{2}{l|}{\textbf{Event}}
    &   \textbf{Destination state} 
        &   \textbf{Trans. rate} 
            &   \textbf{Condition}                              \\
\midrule
&   $PU$ AR. A vacant channel exists in the NCRN.
    &   (i_{n}+1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f)
        &   \lambda_P   &   \text{At least one vacant channel exists in the NCRN; } B_n(x)< M-R(x)                                                \\
&   $PU$ AR. No vacant channel exists in the NCRN. $SU_{2N}$ terminates
    &   (i_{n}+1,j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f)
        &   \lambda_P   &   B_n(x)=M– R(x); j_{n2} > 0          \\
&   $PU$ AR. No vacant channel exists in the NCRN. $SU_{1N}$ performs HO to the RCRN.
    &   (i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1}+1,j_{r2},f)
        &   \lambda_P   &   B_n(x) = M – R(x); j_{n2}=0; j_{n1} > 0: B_r(x) < R(x)   \\
&   $PU$ AR. An $SU_{1N}$ terminates.
    &   (i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f)
        &   \lambda_P   &   B_n(x) = M – R(x); j_{n2}=j_{r2}=0; j_{n1} > 0; B(x)=M    \\ 
&   $SU_{1N}$ AR. A vacant channel exists in the NCRN.
    &   (i_{n},j_{n1}+1,j_{n2},i_{r},j_{r1},j_{r2},f)   
        &   \lambda_S   &   B_n(x) < M – R(x); B(x) < M         \\
&   $SU_{1N}$ AR. No vacant channel exists in the NCRN. $SU_{2N}$ terminates.
    &   (i_{n},j_{n1}+1,j_{n2}-1,i_{r},j_{r1},j_{r2},f)
        &   \lambda_S   &   B_n(x)=M – R(x); j_{n2} > 0         \\
&   $SU_{2N}$ AR. A vacant channel exists in NCRN
    &   (i_{n},j_{n1},j_{n2}+1,i_{r},j_{r1},j_{r2},f)   
        &   \lambda_S   &   B_n(x) < M – R(x)                   \\
&   $SU_{2N}$ AR. No vacant channel exists in NCRN. Vacant channel exists in RCRN.
    &   (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}+1,f)
        &   \lambda_S   &   B_n(x)=M – R(x); B_r(x) < R(x)    \\
&   $PU$ DP from the NCRN.
    &   (i_{n}-1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f)
        &   i_n\;\mu_P  &   \text{There is at least one $PU$ service in the NCRN; } i_n>0. \\
&   $PU$ DP from the RCRN.
    &   (i_{n},j_{n1},j_{n2},i_{r}-1,j_{r1},j_{r2},f)
        &   i_r\;\mu_P &    Ir > 0              \\
&   $SU_{1N}$ DP from the NCRN.
    &   (i_{n},j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f)
        &   J_{n1}\;\mu_S   &   j_{n1} > 0      \\
&   $SU_{1N}$ DP from the RCRN.
    &   (i_{n},j_{n1},j_{n2},i_{r},j_{r1}-1,j_{r2},f)
        &   j_{r1}\;\mu_S   &   Jr > 0          \\
&   $SU_{2N}$ DP from the NCRN.
    &   (i_{n},j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f)
        &   j_{n2}\;\mu_S   &   j_{n2} > 0     \\
&   $SU_{2N}$ DP from the RCRN.
    &   (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}-1,f)
        &   j_{r1}\;\mu_S   &   j_{r1} > 0    \\
&   Idle channel failure.
    &   (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)
        &   (M-B(x))\;\lambda_F &   \text{There is at least one idle channel in the CRN; } B(x)<M     \\
&   An occupied channel fails. An idle channel exists in the CRN.
    &   (in,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)
        &   (B(x)-f)\;\lambda_F &   F<B(x)<M  \\
&   An occupied channel fails. No idle channels exist in the CRN. An $SU_{1N}$ terminates. 
    &   (i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f+1)
        &   (M-f)\;\lambda_F    &   B(x) = M; j_{n1}>0;j_{n2}=j_{r2}=0\\
&   An occupied channel fails. No idle channels exist in the CRN. An $SU_{2N}$ terminates.
    &   (i_{n}+1,j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f+1)
        &   (M-f)\;\lambda_F    &   B(x)=M; j_{n2} > 0    \\
&   An occupied channel fails. No idle channels exist in the CRN. A $PU_{N}$ terminates
    &   (i_{n}-1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)
        &   (M-f)\;\lambda_F    &   B(x) = M; j_{n1}= j_{n2}=j_{r2}=0; i_{n}>0; \\
&   An occupied channel fails. No idle channels exist in the CRN. An $SU_{1R}$ terminates
    &   (i_{n},j_{n1},j_{n2},i_{r},j_{r1}-1,j_{r2},f+1) 
        &   (M-f)\;\lambda_F    &   B(x)=M; B_n(x) = 0; j_{r2}=0; j_{r1}>0; j_{n1}=0;\\
&   An occupied channel fails. No idle channels exist in the CRN. An $SU_{2R}$ terminates
    &   (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}-1,f+1)
        &   (M-f)\;\lambda_F    &   B(x)=M; B_n(x)=M-R(x); j_{r2} > 0. \\
&   An occupied channel fails. No idle channels exist in the CRN. A $PU_R$ terminates
    &   (i_{n},j_{n1},j_{n2},i_{r}-1,j_{r1},j_{r2},f+1) 
        &   (M-f)\;\lambda_F    &   B(x)=M; B_n(x)=j_{r1}=j_{r2}=j_{n2}=0; i_{r}>0\\
&   A failed channel is repaired
    &   (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f-1)   
        &   F\;\mu_R   &   f>0          \\
\bottomrule
\end{tabularx}
\end{table}
\end{document}

使用的是tabularx，行自动编号，...

在此处输入图片描述

答案2

没有太多的变化，我添加了两个包（booktabs 和 array），删除了所有 \hline 命令并更改了表格的定义，如您所见：

\documentclass[10pt]{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\usepackage{relsize}
\usepackage{rotating}
\usepackage{lscape}
\usepackage{changepage}
\usepackage{geometry}
\usepackage{makecell}
\usepackage[utf8]{inputenc}
\usepackage{booktabs}%% <= new
\usepackage{array}%% <= new
\geometry{legalpaper, landscape, margin=0.2in}
\begin{document}
    %\begin{adjustwidth}{-8cm}{}
    %\begin{landscape}
    \renewcommand{\arraystretch}{1.5}
    \renewcommand{\tabcolsep}{1mm}
    \begin{table}
      \begin{tabular}{>{\bfseries}lb{.35\linewidth}@{\hspace{2em}}l@{\hspace{2em}}l@{\hspace{2em}}p{.3\linewidth}}\toprule                
        \textbf{Event}&\textbf{Destination state}&\textbf{Trans. rate}&\textbf{Condition}\\\midrule
1.& $PU$ AR. A vacant channel exists in the NCRN.&$(i_{n}+1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f)$&$\lambda_P$&At least one vacant channel exists in the NCRN;$B_n(x)< M-R(x)$\\ 
2.& $PU$ AR. No vacant channel exists in the NCRN.$SU_{2N}$  terminates&$(i_{n}+1,j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f)$&$\lambda_P$&$B_n(x)=M– R(x); j_{n2} > 0$\\
3.& $PU$ AR. No vacant channel exists in the NCRN.$SU_{1N}$ performs HO to the RCRN.&$(i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1}+1,j_{r2},f)$&$\lambda_P$&$B_n(x) = M – R(x); j_{n2}=0; j_{n1} > 0: B_r(x) < R(x)$\\
4.& $PU$ AR. An $SU_{1N}$ terminates.&$(i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f)$&$\lambda_P$&$B_n(x) = M – R(x); j_{n2}=j_{r2}=0; j_{n1} > 0; B(x)=M$\\
5.&$SU_{1N}$ AR. A vacant channel exists in the NCRN.&$(i_{n},j_{n1}+1,j_{n2},i_{r},j_{r1},j_{r2},f)$&$\lambda_S$&$B_n(x) < M – R(x); B(x) < M$\\
6.& $SU_{1N}$ AR. No vacant channel exists in the NCRN. $SU_{2N}$ terminates.&$(i_{n},j_{n1}+1,j_{n2}-1,i_{r},j_{r1},j_{r2},f)$&$\lambda_S$&$B_n(x)=M – R(x); j_{n2} > 0$\\
7.& $SU_{2N}$ AR. A vacant channel exists in NCRN&$(i_{n},j_{n1},j_{n2}+1,i_{r},j_{r1},j_{r2},f)$&$\lambda_S$&$B_n(x) < M – R(x)$\\
8.& $SU_{2N}$ AR. No vacant channel exists in NCRN. Vacant channel exists in RCRN.&$(i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}+1,f)$&$\lambda_S$&$B_n(x)=M – R(x); B_r(x) < R(x)$\\
9.& $PU$ DP from the NCRN.&$(i_{n}-1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f)$&$i_n\;\mu_P$&There is at least one $PU$ service in the NCRN; $i_n>0$.\\
10.& $PU$ DP from the RCRN.&$(i_{n},j_{n1},j_{n2},i_{r}-1,j_{r1},j_{r2},f)$&$i_r\;\mu_P$&$Ir > 0$\\
11.& $SU_{1N}$ DP from the NCRN.&$(i_{n},j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f)$&$J_{n1}\;\mu_S$&$j_{n1} > 0$\\
12.& $SU_{1N}$ DP from the RCRN. &$(i_{n},j_{n1},j_{n2},i_{r},j_{r1}-1,j_{r2},f)$&$j_{r1}\;\mu_S$&$Jr > 0$\\
13.& $SU_{2N}$ DP from the NCRN.&$(i_{n},j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f)$&$ j_{n2}\;\mu_S$&$ j_{n2} > 0$\\
14.& $SU_{2N}$ DP from the RCRN.&$(i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}-1,f)$&$j_{r1}\;\mu_S$&$j_{r1} > 0$\\
15.& Idle channel failure.&$(i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)$&$(M-B(x))\;\lambda_F$&There is at least one idle channel in the CRN; $B(x) < M$\\
16.& An occupied channel fails. An idle channel exists in the CRN.&$(in,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)$&$(B(x)-f)\;\lambda_F$&$F<B(x)<M$ \\
17.& An occupied channel fails. No idle channels exist in the CRN. An $SU_{1N}$ terminates.  &$(i_{n}+1,j_{n1}-1,j_{n2},i_{r},j_{r1},j_{r2},f+1)$&$(M-f)\;\lambda_F$&$B(x) = M; j_{n1}>0;j_{n2}=j_{r2}=0$\\
18.& An occupied channel fails. No idle channels exist in the CRN. An $SU_{2N}$ terminates.&$    (i_{n}+1,j_{n1},j_{n2}-1,i_{r},j_{r1},j_{r2},f+1)$&$(M-f)\;\lambda_F$&$B(x)=M; j_{n2} > 0$\\
19.& An occupied channel fails. No idle channels exist in the CRN. A $PU_{N}$ terminates&$  (i_{n}-1,j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f+1)$&$
                 (M-f)\;\lambda_F$&$B(x) = M; j_{n1}= j_{n2}=j_{r2}=0; i_{n}>0;$ \\
20.& An occupied channel fails. No idle channels exist in the CRN. An $SU_{1R}$ terminates&$ (i_{n},j_{n1},j_{n2},i_{r},j_{r1}-1,j_{r2},f+1)$&$(M-f)\;\lambda_F$&$B(x)=M; B_n(x) = 0; j_{r2}=0; j_{r1}>0; j_{n1}=0;$\\
21.& An occupied channel fails. No idle channels exist in the CRN. An $SU_{2R}$ terminates&$ (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2}-1,f+1)$&$(M-f)\;\lambda_F$&$B(x)=M; B_n(x)=M-R(x); j_{r2} > 0.$ \\
22.& An occupied channel fails. No idle channels exist in the CRN. A $PU_R$ terminates&$ (i_{n},j_{n1},j_{n2},i_{r}-1,j_{r1},j_{r2},f+1)$&$(M-f)\;\lambda_F$&$B(x) = M; B_n(x)=j_{r1}=j_{r2}=j_{n2}=0; i_{r}>0$\\
23.& A failed channel is repaired&$  (i_{n},j_{n1},j_{n2},i_{r},j_{r1},j_{r2},f-1)$&$F\;\mu_R$&$f>0$\\\bottomrule
    \end{tabular}
\end{table}
\renewcommand{\arraystretch}{1}
\end{document}

好吧，如果我不将字体大小减小到 10 pt，它将无法放在一页中。原因是您的行数比示例图片中多了一些。

要获得粗体数字，您必须将每个数字都加粗。最好有一个粗体打印列，因此我添加了第一列，其中的数字为\bfseries。

看起来像这样：

复杂表格

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