\node[and port, number inputs=3, yscale=1] (and1) at (0, 0) {};
\node[or port, yscale=1.6, xscale=1] (or1) at (3.5, 0.45) {};
\node[or port, number inputs=3] (or2) at (0,-2.01) {};
\node[and port] (and2) at (5.5,-1.73) {};
\node (in1) at ($(and1.in 1) - (1, 0)$) {};
\node (in2) at ($(and1.in 2) - (1, 0)$) {};
\node (in3) at ($(and1.in 3) - (1, 0)$) {};
\node (in4) at ($(or1.in 4) - (4.5, -2.68)$) {};
\node (in5) at ($(or2.in 3) - (1, -0.75)$) {};
\node (in6) at ($(or2.in 3) - (1, -0.35)$) {};
\node (in7) at ($(or2.in 3) - (1, 0)$) {};
\node at (in1) {\(y\)};
\node at (in2) {\(z\)};
\node at (in3) {\(t\)};
\node at (in4) {\(x\)};
\node at (in5) {\(y\)};
\node at (in6) {\(z\)};
\node at (in7) {\(t\)};
\draw (in1) -- (and1.in 1) ;
\draw (in2) -- (and1.in 2);
\draw (in3) -- (and1.in 3);
\draw (in4) -- (or1.in 1);
\draw (in5) -- (or2.in 1);
\draw (in6) -- (or2.in 2);
\draw (in7) -- (or2.in 3);
\draw (and1.out) -- (or1.in 2) node[above] {\(y+z+t\)};
\draw (or2.out) -- ++ (1, 0) node[below] {\(yzt\)};
\draw (or1.out) -| (and2.in 1) node[left] {$x(y+z+t)$};
\draw (or2.out) -- (and2.in 2) ++ (1.5, 0) node[right] {$x(y+z+t)+yzt$};
\draw (and2.out) -- ++ (0.5,0);
\end{circuitikz}
这让我
显然我需要y+z+t稍微调整一下左侧和x(y+z+t)右上方。我该怎么做？
答案1
\draw (or1.out) -| (and2.in 1) node[left, xshift=-1cm] {$x(y+z+t)$};
node [above left=12mm and 15mm of A] {P};
\draw (or2.out) -- (and2.in 2) ++ (1.5, 0) node[right, xshift=1cm, yshift=1cm] {$x(y+z+t)+yzt$};