我目前正在尝试创建一个大型流程图。我已将示例精简到只有方框的部分，我对此有些困惑（这些方框下面会有更多的方框）。我尝试将这些方框并排放置，如果可能的话，尽可能留出尽可能多的空间，但仍适合页面。我曾尝试以某种方式使用范围，但我无法正确使用它。
以下是 MWE：
\documentclass{article}
\usepackage[latin1]{inputenc}
\usepackage{tikz}
\usetikzlibrary{positioning, fit, calc}
\newcommand{\matr}[1]{\mathbf{#1}}
\newcommand{\X}{\matr{X}} %Matrix von X
\begin{document}
%Tikz Stuff
\tikzstyle{block} = [rectangle, draw, fill=blue!70!red!10, node distance=10ex, text centered, rounded corners, text width=30ex, minimum height=5ex]
\tikzstyle{intblock} = [rectangle, draw, node distance=10ex, text centered, rounded corners, text width=25ex, minimum height=5ex]
\begin{figure}
\centering
\begin{tikzpicture}
\begin{scope}[local bounding box=left]
%First Block
\node (start) [block, label =below:Input: $\X$, text width=28ex, align = center] {\textbf{1.} Construct knockoffs $\tilde{\X}$};
\node (a)[below left = 0.5cm of start, align = center]{$n \geq 2p$};
\node (b) [below right = 0.5cm of start, align=center]{$p \leq n < 2p$\\ Extend rows};
\node (c) [intblock, below = 1.5cm of start]{Optmize for $\matr{s}$ (SDP/equi-correlation)};
\node (d) [intblock, below = 1cm of c]{Calculate $\tilde{\X}$ (Theorem \ref{theorem:knockoff})};
\node (ddd) [below = 0.1cm of d, align=center]{Output: $\tilde{\X}$ satisfying 2.1};
\node (dd) [fit=(start) (a) (b) (ddd),draw,dotted,black] {};
\node (e) [block, below = of d]{\textbf{2.} Calculate $(W_1,\dots,W_p)$ obeying 2.2 $\&$ 2.3};
\end{scope}
\draw [->] (start) -| (a);
\draw [->] (start) -| (b);
\draw [->] (a) |- (c);
\draw [->] (b) |- (c);
\draw [->] (c) -- (d);
\draw [->] (ddd) -- (e);
%First Block end
%Second block
\begin{scope}[local bounding box=right, xshift=6cm]
\node (xstart) [block, label =below:Input: $\X$] {\textbf{1.} Construct knockoffs $\tilde{\X}$};
\node (xa) [intblock, below = of xstart] {Algorithm for knockoff sampler $P_{\tilde{X}|X}$};
\node (xb) [intblock, below = of xa ] {Sample $\tilde{\X} \sim P_{\tilde{X}|X}$};
\node (xd) [below = 0.1cm of xb, align=center]{Output: $\tilde{\X}$ $(\approx)$ satisfying Definition 4.2};
\node (xdd) [fit=(xstart) (xa) (xb) (xd),draw,dotted,black] {};
\node (e) [block, below = of xd]{\textbf{2.} Calculate $(W_1,\dots,W_p)$ obeying 3.1};
\draw [->] (xd) -- (e);
\end{scope}
%Second block end
\end{tikzpicture}
\end{figure}
\end{document}
本质上，我想要左边的第一个框和右边的第二个框。
答案1
\documentclass{article}
\usepackage[latin1]{inputenc}
\usepackage{tikz}
\usetikzlibrary{positioning, fit, calc}
\newcommand{\matr}[1]{\mathbf{#1}}
\newcommand{\X}{\matr{X}} %Matrix von X
\begin{document}
%Tikz Stuff
\tikzstyle{block} = [rectangle, draw, fill=blue!70!red!10, node distance=10ex, text centered, rounded corners, text width=30ex, minimum height=5ex]
\tikzstyle{intblock} = [rectangle, draw, node distance=10ex, text centered, rounded corners, text width=25ex, minimum height=5ex]
\begin{figure}
\centering
\begin{tikzpicture}
\begin{scope}[local bounding box=left, xshift=-6cm]
%First Block
\node (start) [block, label =below:Input: $\X$, text width=28ex, align = center] {\textbf{1.} Construct knockoffs $\tilde{\X}$};
\node (a)[below left = 0.5cm of start, align = center]{$n \geq 2p$};
\node (b) [below right = 0.5cm of start, align=center]{$p \leq n < 2p$\\ Extend rows};
\node (c) [intblock, below = 1.5cm of start]{Optmize for $\matr{s}$ (SDP/equi-correlation)};
\node (d) [intblock, below = 1cm of c]{Calculate $\tilde{\X}$ (Theorem \ref{theorem:knockoff})};
\node (ddd) [below = 0.1cm of d, align=center]{Output: $\tilde{\X}$ satisfying 2.1};
\node (dd) [fit=(start) (a) (b) (ddd),draw,dotted,red, ultra thick] {};
\node (e) [block, below = of d]{\textbf{2.} Calculate $(W_1,\dots,W_p)$ obeying 2.2 $\&$ 2.3};
\end{scope}
\draw [->] (start) -| (a);
\draw [->] (start) -| (b);
\draw [->] (a) |- (c);
\draw [->] (b) |- (c);
\draw [->] (c) -- (d);
\draw [->] (ddd) -- (e);
%First Block end
%Second block
\begin{scope}[local bounding box=right, xshift=3cm]
\node (xstart) [block, label =below:Input: $\X$] {\textbf{1.} Construct knockoffs $\tilde{\X}$};
\node (xa) [intblock, below = of xstart] {Algorithm for knockoff sampler $P_{\tilde{X}|X}$};
\node (xb) [intblock, below = of xa ] {Sample $\tilde{\X} \sim P_{\tilde{X}|X}$};
\node (xd) [below = 0.1cm of xb, align=center]{Output: $\tilde{\X}$ $(\approx)$ satisfying Definition 4.2};
\node (xdd) [fit=(xstart) (xa) (xb) (xd),draw,dotted,green, ultra thick] {};
\node (e) [block, below = of xd]{\textbf{2.} Calculate $(W_1,\dots,W_p)$ obeying 3.1};
\draw [->] (xd) -- (e);
\end{scope}
%Second block end
\end{tikzpicture}
\end{figure}
\end{document}