矩阵中的水平线

Question

这个问题是从帖子中找到的这里如何移动水平虚线，使其稍微远离上标“T”？此外，当移动这条水平线时，如何水平对齐所有三条水平虚线？这是从原始链接中找到的解决方案代码：

\documentclass{article}
\usepackage{amsmath}
\usepackage{arydshln}


\begin{document}

\begin{equation}
\left[
    \begin{array}{c;{2pt/2pt}c}
        N & B_i \\ \hdashline[2pt/2pt]
        B_i^T & 0 
    \end{array}
\right]
\left[
    \begin{array}{c}
        x_i \\ \hdashline[2pt/2pt]
        k
    \end{array}
\right]
=\left[
    \begin{array}{c}
        n \\ \hdashline[2pt/2pt]
        0
    \end{array}
\right]
\text{ with } n = A^TPl
\end{equation}

\end{document}

Answer 1

改变\arraystretch：

\renewcommand{\arraystretch}{1.4}   %% adjsut as you wish

代码：

\documentclass{article}
\usepackage{amsmath}
\usepackage{arydshln}


\begin{document}

\begin{equation}
\renewcommand{\arraystretch}{1.4}
\left[
    \begin{array}{c;{2pt/2pt}c}
        N & B_i \\ \hdashline[2pt/2pt]
        B_i^T & 0
    \end{array}
\right]
\left[
    \begin{array}{c}
        x_i \\ \hdashline[2pt/2pt]
        k
    \end{array}
\right]
=\left[
    \begin{array}{c}
        n \\ \hdashline[2pt/2pt]
        0
    \end{array}
\right]
\text{ with } n = A^TPl
\end{equation}

\end{document}

您还可以定义\strut自己的

\newcommand{\mystrut}{\rule{0pt}{2.5ex}}

并像使用它一样

\documentclass{article}
\usepackage{amsmath}
\usepackage{arydshln}
\newcommand{\mystrut}{\rule{0pt}{2.5ex}}

\begin{document}

\begin{equation}
%\renewcommand{\arraystretch}{1.4}
\left[
    \begin{array}{c;{2pt/2pt}c}
        N & B_i \\ \hdashline[2pt/2pt]
        \mystrut B_i^T & 0
    \end{array}
\right]
\left[
    \begin{array}{c}
        x_i \\ \hdashline[2pt/2pt]
        \mystrut k
    \end{array}
\right]
=\left[
    \begin{array}{c}
        n \\ \hdashline[2pt/2pt]
       \mystrut 0
    \end{array}
\right]
\text{ with } n = A^TPl
\end{equation}

\end{document}